You should add -77 to 77 because it will cancel out.
Option A: z + 1
Option B: 6 + w
Option D: 
Solution:
Let us first define the polynomial.
A polynomial can have constants, variables, exponents and fractional coefficients.
A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.
<u>To find which expressions are polynomial:</u>
Option A: z + 1
By the definition, z + 1 is a polynomial.
It is polynomial.
Option B: 6 + w
By the definition, 6 + w is a polynomial.
It is polynomial.
Option C: ![y^{2}-\sqrt[3]{y}+4](https://tex.z-dn.net/?f=y%5E%7B2%7D-%5Csqrt%5B3%5D%7By%7D%2B4)
![y^{2}-\sqrt[3]{y}+4=y^{2}-{y}^{1/3}+4](https://tex.z-dn.net/?f=y%5E%7B2%7D-%5Csqrt%5B3%5D%7By%7D%2B4%3Dy%5E%7B2%7D-%7By%7D%5E%7B1%2F3%7D%2B4)
Here, y have fractional exponent.
So, it is not a polynomial.
Option D:
By the definition, is a polynomial.
It is polynomial.
Hence z + 1, 6 +w and are polynomials.
From the table, the experimental Probability of rolling a 1 = 28/200 = 7/50
So for 25 rolls we would expect 7 * 25 / 50 = 3.5
answer: 4 times
Answer: Around 96 people would prefer creamy peanut butter.
Step-by-step explanation:
In the survey was found that 4 out of 5 preferred creamy over chunky peanut butter.
Then the relative frequency is:
4/5 = 0.8 prefer creamy peanut butter.
And we can assume that:
1/5 = 0.2 prefer chunky peanut butter.
We also could multiply these numbers by 100% to obtain the percentage forms:
0.8*100% = 80%
0.2*100% = 20%
Now, if there are 120 people in the grocery store, we can expect that the 80% will prefer creamy peanut butter.
Then we can expect that the number of people that prefers creamy peanut butter is:
N = (80%/100%)*120 = 0.8*120 = 96
Around 96 people would prefer creamy peanut butter.
Answer:
A, C, E
Step-by-step explanation:
Associative
Commutative
Exponent Property
I think that it the correct answer!
Have a great day/night :)
