Find the product:
(r+2)(r-5)(r-2)(r+5)
Please show all steps.
15 points.
2 answers:
Hello from MrBillDoesMath!
Answer:
r^4- 29r^2 + 100
Discussion:
Rearrange the terms in the product as follows:
(r+2)(r-2) * (r-5)(r+5) =
(r^2 - 4) * (r^2-25) =
f^4 - (25+4)r^2 + 4*25 =
r^4- 29r^2 + 100
Thank you,
MrB
by rearranging and foiling them
(r+2)(r-2)(r+5)(r-5)
![{r }^{2} - 4](https://tex.z-dn.net/?f=%20%7Br%20%7D%5E%7B2%7D%20%20-%204)
![{r}^{2} - 25](https://tex.z-dn.net/?f=%20%7Br%7D%5E%7B2%7D%20%20-%2025)
now foil them
r^4-25r^2-4r^2+100
r^4-29r^2+100
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