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zzz [600]
3 years ago
7

A football team lost five yards on each of two consecutive plays. Find the total change in yardage.

Mathematics
1 answer:
maria [59]3 years ago
8 0

Answer:

The change is a loss of 10 yards, so -10 yards.

Step-by-step explanation:

The total change in yardage after 2 plays is the sum of the yardage of each play.

What lost yardage means?

Lost yardage means negative yardage.

Imagine that in a Buffalo Bills game, Devin Singletary lost 2 yards on his first carry. So his total yardage is -2.

If in the next carry he gets 3 yards, his total yardage is 1. If he loses 1, his total yardage is -3.

First play

Loss of 5 yards.

So the first play counts for -5 yards.

Second play

Loss of 5 yards.

So the second play counts for -5 yards.

Total

-5 - 5 = -10

The change is a loss of 10 yards, so -10 yards.

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How to solve 93+(68+7) using the properties.
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C.P.=RS 180 S.P. =Rs 200 solve it step by step 'I'll give u brainest'​
lubasha [3.4K]

Answer:

Rs20

Step-by-step explanation:

C.P=Rs180

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7 0
3 years ago
A dairy farmer plans to enclose a rectangular pasture adjacent to a river. To provide enough grass for the herd, the pasture mus
AysviL [449]

Answer:

390 m (perpendicular to river) x 780 m (parallel to river)

Step-by-step explanation:

Let y be the length of the side parallel to the river, and let x be the length of the sides perpendicular to the river.

The total area and length of fence required are given by:

Rewriting the length of fence as a function of only x:

The value of x for which the derivate of L(x) is zero is the length of x that uses the least amount of fencing:

If x = 390 m, then:

The dimensions that will use the least amount of fencing are 390 m x 780 m

3 0
3 years ago
A turtle lives in a garden and a hedgehog lives in the woods. They leave their homes at the same time walk toward each other and
Jlenok [28]

Based on the calculations, the distance between the garden and the woods is equal to 383 meters.

<h3>How to calculate the distance.</h3>

First of all, we would assign a variable to the different speeds of the turtle and hedgehog as follows:

  • Let the turtle's speed be S₁.
  • Let the hedgehog's speed be S₂.

Mathematically, distance is given by this formula:

Distance = speed × time

Translating the word problem into an algebraic expression, we have;

If they both meet in 5 hours:

D = (S₁ + S₂) × 5  

D = 5S₁ + 5S₂      ......equation 1.

Turtle's speed is 10 meters per hour slower than the hedgehog:

S₁ = S₂ - 10    .....equation 2.

If the turtle had left home 4.5 hours earlier than the hedgehog had left his home:

9.5S₁ + 5S₂ = D + 150    .....equation 3.

Substituting enq. 2 into eqn. 1, we have:

D = 5(S₂ - 10) + 5S₂

D = 5S₂ - 50 + 5S₂

D = 10S₂ - 50      .....equation 4.

Equating eqn. 3 and eqn. 4, we have:

10S₂ - 50 = 9.5(S₂ - 10) + 5S₂ - 150

10S₂ - 50 = 9.5S₂ - 95 + 5S₂ - 150

10S₂ - 50 = 14.5S₂ - 245

14.5S₂ - 10S₂ = 245 - 50

4.5S₂ = 195

S₂ = 195/4.5

S₂ = 43.3 m/h.

Now, we can find the distnace:

D = 10S₂ - 50

D = 10(43.3) - 50

D = 433 - 50

D = 383 meters.

Learn more about distance here: brainly.com/question/10545161

4 0
2 years ago
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