Answer:
- 3 (die)
- 4 (slips)
- 6 (spinner)
- 5 (ace)
Step-by-step explanation:
Josie rolls a six-sided die 18 times. What is the estimated number of times she rolls a two? 3 = (1/6)(18)
Slips of paper are numbered 1 through 10. If one slip is drawn and replaced 40 times, how many times should the slip with number 10 appear? 4 = (1/10)(40)
A spinner consists of 10 equal- sized spaces: 2 red, 3 black, and 5 white. If the spinner is spun 30 times, how many times should it land on a red space? 6 = (2/10)(30)
A card is picked from a standard deck of playing cards 65 times and replaced each time. About how many times would the card drawn be an ace? 5 = (4/52)(65)
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The probability of a given event is the number of ways it can occur divided by the number of possibilities. For example, a 2 is one of 6 numbers on a die, so we expect its probability of showing up to be 1/6. The expected number of times it will show up in 18 rolls of the die is (1/6)(18) = 3.
Answer:
A
Step-by-step explanation:
The range is the y values of the function from the least to the greatest. To find it find the furthest point up and down. Draw a horizontal line from the point to the y-axis to identify the y value. Here the function extends from -3 to 6. So the range is 
.
Answer:
11/12
Step-by-step explanation:
(1 1/10)/(1 1/5) = 1.1/1.2 = 11/12
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You can also work this using improper fractions:
(1 1/10)/(1 1/5) = (11/10)/(6/5) = 11/10×5/6 = (11×5)/(6×10)
= (11×5)/(6×2×5) = 11/(6×2) = 11/12
Answer:
I think that the answer is D (13,20)
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