All I need is the answer to part b and c

Math question please show work for brainliest :)

Aleks04 [339]

It’s 1 I think!

Hope I helped!!! :) :D

4 0

4 years ago

A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),

lana [24]

Answer:

(9) $\frac{1}{12}$ (10) $\frac{1}{12}$ (11) $\frac{5}{12}$ (12) $\frac{1}{4}$ (13) $\frac{1}{6}$ 14) $\frac{5}{36}$ (15) $\frac{1}{12}$ (16)0

Step-by-step explanation:

The sample Space of the single die rolled twice is presented below:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),}.

n(S)=36

(9)Probability of getting two numbers whose sum is 9.

The possible outcomes are: (3, 6), (4, 5), (5, 4)

$P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}$

10) Probability of getting two numbers whose sum is 4.

The possible outcomes are: (1, 3),(2, 2),(3, 1),

$P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}$

11.)Find the probability of getting two numbers whose sum is less than 7.

The possible outcomes are: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (4, 1), (4, 2), (5, 1)

$P(\text{two numbers whose sum is less than 7})=\frac{15}{36}=\frac{5}{12}$

12.Probability of getting two numbers whose sum is greater than 8

The possible outcomes are:(4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)

$P(\text{two numbers whose sum is greater than 8})=\frac{9}{36}=\frac{1}{4}$

(13)Probability of getting two numbers that are the same (doubles).

The possible outcomes are:(1, 1)(2, 2), (3, 3), (4, 4), (5, 5), (6, 6)

$P(\text{two numbers that are the same})=\frac{6}{36}=\frac{1}{6}$

14.Probability of getting a sum of 7 given that one of the numbers is odd.

The possible outcomes are: (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

$P(\text{getting a sum of 7 given that one of the numbers is odd.})=\frac{5}{36}$

(15)Probability of getting a sum of eight given that both numbers are even numbers.

The possible outcomes are: (2, 6), (4, 4), (6, 2)

$P(\text{getting a sum of eight given that both numbers are even numbers.})=\frac{3}{36}\\=\frac{1}{12}$

16.Probability of getting two numbers with a sum of 14.

$P(\text{getting two numbers with a sum of 14.})=\frac{0}{36}=0$

4 0

4 years ago

A population of values has a normal distribution with

Naily [24]

Using the normal distribution, we have that:

For a single value, P(X < 79.1) = 0.5517.

For the sample of n = 155, P(X < 79.1) = 0.9463.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

The mean and the standard deviation are given, respectively, by:

$\mu = 76.2, \sigma = 22.4$ .

The probability is the p-value of Z when X = 79.1, hence:

$Z = \frac{X - \mu}{\sigma}$

Z = (79.1 - 76.2)/22.4

Z = 0.13

Z = 0.13 has a p-value of 0.5517.

Hence: P(X < 79.1) = 0.5517.

For the sample of 155, applying the Central Limit Theorem, the standard error is:

s = 22.4/sqrt(155) = 1.8

Hence:

$Z = \frac{X - \mu}{s}$

Z = (79.1 - 76.2)/1.8

Z = 1.61

Z = 1.61 has a p-value of 0.9463.

P(X < 79.1) = 0.9463.

More can be learned about the normal distribution at brainly.com/question/15181104

#SPJ1

3 0

1 year ago

Find the value of x. Round your answer to the nearest degree.

Lostsunrise [7]

Answer:

x = 20.92°

Step-by-step explanation:

AB² + BC² = AC²

5² + BC² = 14²

BC = 3√19

$\tan(ACB) = \frac{AB}{BC}$

$\tan(x) = \frac{5}{3 \sqrt{19} }$

x = 20.925° ≈ 20.92°

HOPE THIS HELPS AND HAVE A NICE DAY <3

8 0

2 years ago

7+ За = 12 + 2а Can anyone give the answer quick!

andre [41]

Answer:

A=5

Step-by-step explanation:

5 0

3 years ago

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