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gtnhenbr [62]
3 years ago
11

All I need is the answer to part b and c

Mathematics
1 answer:
Reil [10]3 years ago
7 0

Answer: 24, c

Step-by-step explanation:

Looked it up

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Solve the equation using the distributive property and properties of equality
NeTakaya

Answer:

x = 30

Step-by-step explanation:

1/2(x+6) = 18

Distribute

1/2 x + 3 = 18

Subtract 3 from each side

1/2x +3-3 = 18-3

1/2x = 15

Multiply each side by 2

1/2x*2 = 15*2

x = 30

6 0
4 years ago
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Pleaseee help me I’m stuck
antiseptic1488 [7]

Answer:

11

Step-by-step explanation:

3 0
3 years ago
If the statement "If I am hungry, then I am not happy" is assumed to be true, is its inverse, "If I am not hungry, then I must b
elena55 [62]
No -- other factors will influence whether your happy or not. Saying that is true is inductive reasoning, which is prone to error
8 0
3 years ago
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Rectangle STUV has square PQRS removed, leaving an area of 92 m^2. Side PT is 4 m in length and side RV is 8m in length
Andrei [34K]

Answer:

117 m^{2}

Step-by-step explanation:

First think of the square that was removed.  All 4 sides are equal but you don't know the length so lets gives them the variable X.

So to find the area of the rectangle, insert those variables into the area equation for a rectangle.

(RV + (X) ) (PT +(X)) = rectangle area

Now you are given what the area is if you remove the square.  So subtract the the square's area from the equation above and set it equal to the size they told you.

(RV + (X)) (PT + (X))  - [(X)(X)] = 92m^{2}

      rectangle          -  square  =  remaining area

Now plug in the numbers you know and solve for X.

(8 + X) (4 + X) - ((X)(X)) = 92    

Use FOIL to multiply the first part of the equation (first, outer, inner, last)

32 + 8x + 4x + x^{2} -  x^{2}  =  92

32 + 12x = 92

12x = 60

x = 5

So now you know the size of the square.  Each side is 5m.  So add 5m onto the top of the rectangle and onto the side.  The top is 13m and the side is 9m.  The area of the rectangle is the length times the height to 13 x 9 which is 117 m^{2}

6 0
3 years ago
A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi
viktelen [127]

Answer:

Side length = \sqrt{\frac{A}{3} } cm ,   Height =  \frac{1}{2} \sqrt{\frac{A}{3} } cm  ,  Volume = \frac{A\sqrt{A}}{6\sqrt{3} }  cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

  1. y = \frac{A - x^{2} }{4x}

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( \frac{A - x^{2} }{4x} )

V =  \frac{Ax - x^{3} }{4}

To find max volume put V' = 0

So taking derivative equation becomes

\frac{A - 3 x^{2} }{4} = 0

A = 3 x^{2}

x^{2} = \frac{A}{3}

x = \sqrt{\frac{A}{3\\} }

put value of x in equation 1

y = \frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }  

y = \frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }

y = \frac{1}{2} \sqrt{\frac{A}{3} }

So the volume will be

V = x^{2} × y

Put values of x and y from equation 2 & 3

V = \frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )

V = \frac{A\sqrt{A}}{6\sqrt{3} }

8 0
4 years ago
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