Use the Pythagorean theorem since you are working with a right triangle:
a^2+b^2=c^2a2+b2=c2
The legs are a and b and the hypotenuse is c. The hypotenuse is always opposite the 90° angle. Insert the appropriate values:
0.8^2+0.6^2=c^20.82+0.62=c2
Solve for c. Simplify the exponents (x^2=x*xx2=x∗x ):
0.64+0.36=c^20.64+0.36=c2
Add:
1=c^21=c2
Isolate c. Find the square root of both sides:
\begin{gathered}\sqrt{1}=\sqrt{c^2}\\\\\sqrt{1}=c\end{gathered}1=c21=c
Simplify \sqrt{1}1 . Any root of 1 is 1:
c=c= ±11 *
c=1,-1c=1,−1
Answer:
-11w x 7w - 7 x 7
Step-by-step explanation:
Answer:
12780
Step-by-step explanation:
Answer:
3 Credit Courses = 37
4 Credit Courses = 11
Step-by-step explanation:
1. Set up 2 equations:
3x + 4y = 155
x + y = 48
2. Simplify the second expression for x by subtracting y from both sides
x = 48 - y
3. Substitute 48 - y for x
3(48-y) + 4y = 155
4. Simplify the expression by multiplying by 3
144 - 3y +4y = 155
5. Subtract 144 from both sides and subtract 3y from 4y
y = 11 = 4 Credit Courses
6. Substitute y for equation 2
x = 48-11
7. solve for x
x = 37 = 3 Credit Courses