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swat32
2 years ago
12

For a concert, there are $50 reserved seat tickets and $35 general admission tickets. there are 2000 reserved seats available, a

nd the fire code limits the total number of audience members to 3000. the promoter must take in $90,000 in ticket sales to break even. find a system of five inequalities that represents this problem. (let x for the number of general admission tickets and y represent the number of reserved seat tickets. enter your answers as a comma-separated list of inequalities.)
Mathematics
1 answer:
nevsk [136]2 years ago
3 0

The number of seats sold cannot be negative, so you have

... x ≥ 0, y ≥ 0

The limits on numbers of seats must be observed, so you have

... y ≤ 2000

... x + y ≤ 3000

And the revenue constraint must be met:

... 35x + 50y ≥ 90,000

Together, these inequalties are ...

{x ≥ 0, y ≥ 0, y ≤ 2000, x + y ≤ 3000, 35x + 50y ≥ 90,000}

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Answer if you know<br> DO NOT ANSWER IF YOU DO NOT KNOW THE ANSWERS<br><br> Thank you :)
ludmilkaskok [199]

 See below for pics of the answers

6 0
2 years ago
Statements
vazorg [7]

Answer:

See Explanation

Step-by-step explanation:

The question has unclear information.

So, I'll answer from scratch

Given

ABC = Right angled triangle

DB bisects ABC

Required

Prove that CBD = 45

From the question, we have that:

ABC is right angled at B

So, when DB bisects ABC, it means that DB divides ABC into two equal angles.

i.e.

CBD = ABD

and

CBD + ABD = 90

Substitute CBD for ABD in CBD + ABD = 90

CBD + CBD = 90

2CBD = 90

Divide both sides by 2

\frac{2CBD}{2} = \frac{90}{2}

CBD = \frac{90}{2}

CBD = 45

Hence, it is proved that CBD = 45

<em>Follow the above explanation and use it to answer your question properly</em>

6 0
2 years ago
The graph at the right described the money two clubs are earning from fundraising. In how many weeks will the two clubs have the
pickupchik [31]

Answer:

52 weeks

Step-by-step explanation:

The club starting with $270 (club 1) is increasing their bank balance each week by ...

... $280 -270 = $10

The club starting with $10 (club 2) is increasing their bank balance each week by ...

... $25 -10 = $15

Club 2 is gaining on Club 1 by $15 -10 = $5 each week. So, the initial difference of $270 -10 = $260 will be overcome in ...

... $260/($5/week) = 52 weeks

_____

The same result is shown in the attached graph, which also shows that both clubs' bank balances will be $790 at that time.

7 0
3 years ago
A student must have at least 10 hours of instructor-assisted driving time to pass
Solnce55 [7]

Answer:

t ≥ 10

Step-by-step explanation:

Since the student needs at least 10 hours of driving time, they need greater than or equal to 10 hours to pass.

4 0
2 years ago
Choose the option with the proper number of sig figs
marishachu [46]
\text{ 2 }\times10^8

Explanation:\begin{gathered} \text{Given:} \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1} \end{gathered}

let's break down the expression to get the final result:

\begin{gathered} \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = }\frac{9}{4.5}\times\text{ }\frac{10^9}{10^1} \\ \frac{9}{4.5}\text{ = }\frac{9\text{ }\times\text{ 10}}{4.5\text{ }\times\text{ 10}}\text{ = }\frac{90}{45} \\ \frac{9}{4.5}\text{ = }2 \\  \\ \frac{10^9}{10^1}\colon\text{ when we divide exponents with same base, } \\ we\text{ take one of the base and combine the exponents by subtracting them:} \\ \frac{10^9}{10^1}=10^{9-1} \\ \frac{10^9}{10^1}=10^8 \end{gathered}\begin{gathered} \frac{9}{4.5}\times\text{ }\frac{10^9}{10^1}\text{ = 2 }\times10^8 \\  \\ \text{when dividing decimals, }the\text{ least number of }significant\text{ }figures\text{ in the problem}, \\ \text{ }\det ermines\text{ the significant figures in the answer} \\ 9\text{ = 1 significant, 4.5 = 2 significant} \\ \text{The least significant is 1} \\  \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = 2 }\times10^8 \end{gathered}

6 0
1 year ago
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