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3 years ago

Speedeez Go Carts charges $10 plus $2.50 per lap. Which best describes the relationship between total cost and the number

Mathematics

1 answer:

kupik [55]3 years ago

8 0

Answer:

10+2.50*L

Step-by-step explanation:

It first says they charge $10 PLUS $2.50 per lap.

If I were to go only 1 lap my total would be $12.50, that's why the number of laps is labeled L because we don't know how many laps the customer is going to make.

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the circumference of a circle is a(pi) units, and the area of the circle is b(pi) square units. If a=b, what is the radius of th

xxTIMURxx [149]

Answer:

the redius is 0 unit or 1/2^(1/2) unit.

8 0

3 years ago

What is the answer to number 4

laiz [17]

Y=-2x^2+2x-4. Should be correct

3 0

4 years ago

Find the mean of the first 7 odd prime number?

bekas [8.4K]

Answer: 75/7 or 10.71 (rounded)

Step-by-step explanation:

Mean = Average

To find the average you should add all the numbers together and then divide it by the amount of numbers.

In this question, the formula is $\frac{n_1+n_2+n_3+n_4+n_5+n_6+n_7}{7}$

----------------------------------------------------------------------------------------

The list of the first 7 odd prime numbers:

3, 5, 7, 11, 13, 17, 19

Now, add them together

3+5+7+11+13+17+19=75

Divide the sum by 7

75÷7=75/7=10.71 (rounded)

Hope this helps!! :)

Please let me know if you have any questions

6 0

3 years ago

Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

3 0

3 years ago

HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.

GarryVolchara [31]

Answer:

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL) Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0

3 years ago