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4 years ago

Which is the correct way to write three and one-tenth of a milliliter as an Arabic number?

1 answer:

4 0

we have that
three and one-tenth------> 3 1/10--------> (3*10+1)/10--------> 31/10-----> 3.1

the answer is 3.1 ml

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The length of one side of a square is 3n+2. The perimeter of the square is 4(3n+2). Which expression is equivalent to the perime

deff fn [24]

Answer:

4(3n + 2)

Step-by-step explanation:

as we know perimeter of a square is 4 x side

one side is 3n + 2

4 sides = 4(3n +2)

8 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

Riddle

erma4kov [3.2K]

Answer:

100 minutes?

lol

5 0

4 years ago

Read 2 more answers

How to find the slope of the line

finlep [7]

Answer:

Get a line of which you want to know the slope. Make sure that the line is straight.

Pick any two coordinates that the line goes through. Coordinates are the x and y points written as ( x, y ).

Pick which point's coordinates are dominant in your equation. ...

Set up the equation using the y-coordinates on top and the x-coordinates on bottom.

4 0

3 years ago

Find the gradient of the line 3y + 2x = 1 how to guys

kykrilka [37]

Answer:

-2/3

Step-by-step explanation:

The gradient of a line is its slope. You can just convert the equation to slope-intercept form (y=mx+b where "m" is the gradient/slope):

3y + 2x = 1

3y = 1 - 2x

y = 1/3 - 2/3x

y = -2/3x + 1/3

So, as we can see, -2/3 is the gradient/slope of the line.

5 0

3 years ago