Purple flower color is dominant to white flower color. If pure-breeding purple flowering plants are crossed with pure-breeding w
hite flowering plants, what would be the predicted phenotypic ratio of the offspring?
1 answer:
Answer:
The phenotypic ratio of the offspring will be 100% of purple flowers.
Step-by-step explanation:
Mendel's first law states that if two pure lines are crossed for a given character, the descendants of the first generation will all be equal to each other, phenotypically and genotypically, and phenotypically equal to one of the parents (of dominant genotype).
The Punnett square is a square diagram that is used to predict the genotypes of a particular cross or breeding experiment.
We represent the possibilities of hybridization using a Punnett square in the attached picture.
Uppercase letters represent dominant alleles and lowercase letters represent recessive alleles.
Homozygous individuals have the same pair of alleles. (AA, aa)
We can verify that all offspring have a dominant allele, therefore all offspring will have purple flowers.
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Answer:
Step-by-step explanation:
Let
Subbing in:
a = 9, b = -2, c = -7
The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:
Group together in groups of 2:
Now factor out what's common within each set of parenthesis:
We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:
Remember that
so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.
The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring gives us that x = 1 and -1. The other set is a bit more tricky. If
then
and
You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:
±
which will simplify down to
±
Those are the 4 solutions to the quartic equation.