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masya89 [10]
3 years ago
10

Please can some body help me with this!!!! It’s due tomorrow ☹️

Mathematics
1 answer:
Sav [38]3 years ago
5 0

Answer:

x=6

DO=25

OG=35

Step-by-step explanation:

start by solving the length of DG to find x.

DO+OG=60

(4x-3)+(2x+21)=60

6x+18=60

6x=42

x=7

Now plug in x and solve.

DO=4(7)-3

DO=28-3

DO=25

OG=2(7)+21

OG=14+21

OG=35

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weqwewe [10]

Consider the numbers 23,643 and 23,987.

Since both the given numbers have same digits at ten thousands and thousands place.

So, we can'not compare the numbers on the basis of ten thousands and thousands digit.

So, let us consider the number 23,643

Consider the place value of digit at the hundreds place. Since, the digit at hundreds place = 6.

The place value of 6 = 600

Now, let us consider the number 23,987

Consider the place value of digit at the hundreds place. Since, the digit at hundreds place = 9.

Te place value of 9 = 900

Since, 900 > 600

So, 23,643 > 23,987

Therefore, the number 23,987 is greater than the number 23,643.

4 0
3 years ago
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RUDIKE [14]

Answer:

The vertex of this parabola, (-2, 3), can be found by completing the square.

Step-by-step explanation:

The goal is to express this parabola in its vertex form:

g(x) = a\, (x - h)^2 + k,

where a, h, and k are constants. Once these three constants were found, it can be concluded that the vertex of this parabola is at (h,\, k).

The vertex form can be expanded to obtain:

\begin{aligned}g(x)&= a\, (x - h)^2 + k \\ &= a\, \left(x^2 - 2\, x\, h + h^2\right) + k = a\, x^2 - 2\, a\, h\, x + \left(a\,h^2 + k\right)\end{aligned}.

Compare that expression with the given equation of this parabola. The constant term, the coefficient for x, and the coefficient for x^2 should all match accordingly. That is:

\left\lbrace\begin{aligned}& a = 3 \\ & -2\,a\, h = 12 \\& a\, h^2 + k = 15\end{aligned}\right..

The first equation implies that a is equal to 3. Hence, replace the "a\!" in the second equation with 3\! to eliminate \! a:

(-2\times 3)\, h = 12.

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Similarly, replace the "a" and the "h" in the third equation with 3 and (-2), respectively:

3 \times (-2)^2 + k = 15.

k = 3.

Therefore, g(x) = 3\, x^2 + 12\, x + 15 would be equivalent to g(x) = 3\, (x - (-2))^2 + 3. The vertex of this parabola would thus be:

\begin{aligned}&(-2, \, 3)\\ &\phantom{(}\uparrow \phantom{,\,} \uparrow \phantom{)} \\ &\phantom{(}\; h \phantom{,\,} \;\;k\end{aligned}.

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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