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4 years ago

Which number is greatest? A.6.2310^12 B.6.2310^8 C.6.2310^-6 D.6.2310^3

Mathematics

2 answers:

Roman55 [17]4 years ago

8 0

I believe A is the answer

kobusy [5.1K]4 years ago

6 0

For this case, they ask us which of the given numbers, in scientific notation, is greater.

So:

$6.23 * 10 ^ {12} = 6,230,000,000,000$ is equivalent to rolling the decimal 12 times to the right.

$6.23 * 10 ^ 8 = 623,000,000$ is equivalent to rolling the decimal 8 times to the right.

$6.23 * 10 ^ {-6} = 000000623$ is equivalent to rolling the decimal 6 times to the left.

$6.23 * 10 ^ 3 = 6,230$ is equivalent to rolling the decimal 3 times to the right.

Thus, we observe that the greatest number is $6.23 * 10 ^ {12}$

Answer:

Option A

You might be interested in

what is the common ratio of the geometric sequence below? –96, 48, –24, 12, –6, ... a, -2 b,-1/2 c, 2 d, 1/2

marysya [2.9K]

Answer:

Option b is correct.

The common ratio for the given geometric sequence is; $\frac{-1}{2}$

Step-by-step explanation:

The given sequence is; -96, 48 , -24, 12 , -6, .....

Since, given sequence is Geometric

Geometric Sequence in which each term is found by multiplying the previous term by a constant(i.e common ratio)

In general we write geometric sequence as;

$a , ar, ar^2, ar^3 , .....$

where a be the first term and r is the common ratio.

On comparing the given sequence with general geometric sequence;

we get

a = -96 ......[1]

ar = 48 ......[2]

ar^2 = -24 .....[3]

and so on....

To find the common ratio i.e, r;

Divide equation [2] by [1];

$\frac{ar}{a} =\frac{48}{-96}$

Simplify:

$r = \frac{-1}{2}$

Similarly,

by dividing the equation [3] by [2] we get;

$\frac{ar^2}{ar} = \frac{-24}{48}$

Simplify:

$r = \frac{-1}{2}$

As, you can see that the value of r is constant i.e, $r= \frac{-1}{2}$ in the given sequence.

Therefore, the common ratio for the given geometric sequence is; $r= \frac{-1}{2}$

8 0

3 years ago

Read 2 more answers

Let f(x)=(8x^4-3)^3 and g(x)=8x^4-3 given that f(x)=(h g)(x) , find h(x)

Harman [31]

Answer:

$h(x) = x^{3}$

Step-by-step explanation:

$f(x) = (8 \times x^{4}- 3)^{3}$ ------------(1) (given)

$g(x) =(8 \times x^{4}- 3)$ -------------(2) (given)

so,

f(x) = h(g(x)) (given)

= $(g(x))^{3}$ -----(from (1) and (2))

⇒ $h(k) = k^{3}$ -----(taking g(x) = k)

⇒ $h(x) = x^{3}$ is the function.

8 0

3 years ago

If the range of the function f(x)=x/4 is {28, 30, 32, 34, 36}, what is its domain?

avanturin [10]

Y = x/4
x = 4y
domain = {4(28), 4(30), 4(32), 4(34), 4(36)} = {112, 120, 128, 136, 144}

4 0

3 years ago

Which equation does not represent a direct variation?

tatuchka [14]

Okay I think there has been a transcription issue here because it appears to me there are two answers. However I can spot where some brackets might be missing, bear with me on that.

A direct variation, a phrase I haven't heard before, sounds a lot like a direct proportion, something I am familiar with. A direct proportion satisfies two criteria:

The gradient of the function is constant s the independent variable (x) varies

The graph passes through the origin. That is to say when x = 0, y = 0.

Looking at these graphs, two can immediately be ruled out. Clearly A and D pass through the origin, and the gradient is constant because they are linear functions, so they are direct variations.

This leaves B and C. The graph of 1/x does not have a constant gradient, so any stretch of this graph (to y = k/x for some constant k) will similarly not be direct variation. Indeed there is a special name for this function, inverse proportion/variation. It appears both B and C are inverse proportion, however if I interpret B as y = (2/5)x instead, it is actually linear.

This leaves C as the odd one out.

I hope this helps you :)

4 0

4 years ago

Factor this equation 4x^2+12x-7

Levart [38]

$4x^2+12x-7=0\\\\a=4;\ b=12;\ c=-7\\\Delta=b^2-4ac\\\\\Delta=12^2-4\cdot4\cdot(-7)=144+112=256 \ \textgreater \ 0\\\\therefore\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{256}=16\\\\x_1=\dfrac{-12-16}{2\cdot4}=\dfrac{-28}{8}=\boxed{-\dfrac{7}{2}}\\\\x_2=\dfrac{-12+16}{2\cdot4}=\dfrac{4}{8}=\boxed{\dfrac{1}{2}}$

3 0

3 years ago

Which number is greatest? A.6.23*10^12 B.6.23*10^8 C.6.23*10^-6 D.6.23*10^3

Which number is greatest? A.6.2310^12 B.6.2310^8 C.6.2310^-6 D.6.2310^3