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vekshin1
3 years ago
5

Can solve 100 math problems every 4/3 hours. How many math problems does she solve per hour?

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

She can solve 75 questions per hour.

<u>Solution:</u>

Given that, a lady can solve 100 math problems every 4/3 hours.  

We have to find how many math problems does she can solve per hour?

Now, according to the given information.

In \frac{4}{3} hours ⇒ 100 problems

Then, 1 hour ⇒ "n" problems

So, by chris cross method.

\frac{4}{3} \times n = 1 \times 100

\frac{4}{3}n = 100

n = \frac{3}{4} \times 100\\\\n = 3 \times 25 = 75

Hence, she can solve 75 questions per hour.

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Which of the series below converge? 1 + 9 + 81 + 729 + … 1 + 0.25 + 0.0625 + 0.015625 + … 625 – 125 + 25 – 5 + … 8 – 16 + 32 – 6
Vanyuwa [196]

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6 0
3 years ago
What 2 numbers added give you 32
bixtya [17]
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4 0
3 years ago
Can someone please help me-
puteri [66]

Answer:

can be expressed as decimal: 0.025

s= 1.025* $250

 = $256.25

after 8 years

s= $250* 1.025^8

 ~$304.6

earned $54.6

Step-by-step explanation:

2 and a half is equivilant to 2.5

because it is a % (out of 100) move the decimal 2 places down

2.5-->0.25-->0.025

so can be expressed as decimal: 0.025

interest after 1 year is:

original amount of money * (interest rate+1.0)

+1 because you are adding on to 100%. you already have 100%.  if it was just the interest rate, the amount of money would go down.

so

s= 1.025* $250

=1.025* 250

=256.25

interest after 8 years,

that means you have to take the original, and multiply it by the interest rate, then the new original multiply by intrest rate a total of 8 times

to do this use an exponent, because exponents base the total off the total before them. if that makes any sense srry

s= $250* 1.025^8

 ~$304.6  (I used calculator)

to get her earnings, subtract the new amount of money with her original amount of money

304.6-250

=54.6

$54.6

hope this helps

4 0
2 years ago
Read 2 more answers
Can someone please help
finlep [7]
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3 years ago
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