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MArishka [77]
3 years ago
15

Im going to give 20 points for this question please answer the question

Mathematics
2 answers:
Nastasia [14]3 years ago
7 0
D, 6/16 square foot. This is because 8 and 4 and 2 all can go into 16 more simply than 32.
AVprozaik [17]3 years ago
7 0
The area is merely A = base * height.

The base is (3/4) ft - (1/8) ft = 6/8 ft - 1/8 ft = 5/8 ft.
The height is 1/2 ft.

The area of the parallelogram is (5/8 ft)(1/2 ft)= 5/16 square foot
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The Malcolms are taking a trip. Midville is 214 miles
Juliette [100K]

Answer:

642 miles

Step-by-step explanation:

Distance of Midville from their home = 214 miles

Walesburg is 3 times as far.

How far is Walesburg from their home?

Distance of Walesburg from their home = 3 × Distance of Midville from their home

= 3 × 214 miles

= 642 miles

Distance of Walesburg from their home = 642 miles

8 0
3 years ago
3) Divide x3 + 4x2 – 3x – 12 by (x + 4)
alex41 [277]

Answer:

Factor the numerator and denominator and cancel out the common factors.

x ^2 − 3 is your final answer.

Step-by-step explanation:

Hope that this helps you out! :)  

If you have any questions please put them in the comment section below this answer.  

Have a great rest of your day/night!  

Please thank me on my profile if this answer has helped you.

7 0
2 years ago
Find the hypotenuse of a right triangle that has one side of 7 cm and another<br> one of 3 cm.
Over [174]
The hypotenuse is the square root of 58.
a^2+b^2=c^2
7^2+3^2=c^2
49+9=c^2
58=c^2
c= square root of 58
5 0
2 years ago
Read 2 more answers
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
atroni [7]

Answer: y=Ce^(^3^t^{^9}^)

Step-by-step explanation:

Beginning with the first differential equation:

\frac{dy}{dt} =27t^8y

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

\frac{1}{y} \frac{dy}{dt} =27t^8

Multiply both sides by 'dt' to get:

\frac{1}{y}dy =27t^8dt

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt

ln(y)=27(\frac{1}{9} t^9)+C

ln(y)=3t^9+C

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)

y=e^(^3^t^{^9} ^+^C^)

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

y=e^(^3^t^{^9}^)e^C

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

y=Ce^(^3^t^{^9}^)

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8

Now check if the derivative equals the right side of the original differential equation:

(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)

Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0
2 years ago
A company produces 4.56 times 10 Superscript 3 light bulbs each week. Written in scientific notation, which is the best estimate
artcher [175]
Socratic said
(C) 4.5 times 10 Superscript 6 light bulbs
6 0
3 years ago
Read 2 more answers
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