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3 years ago

Please answer this question now

Mathematics

1 answer:

Luda [366]3 years ago

4 0

Answer:

Step-by-step explanation:

You know that angle Y is a right angle because XY is the radius and YZ is a tangent to the circle. So, you can use the pythagorean theorem to find the third side:

XY^2+4^2=5^2

XY^2+16=25

XY^2=9

XY=3

Hope this was helpful! :)

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Triangle ABC has vertices at A(1,2) B(4,6) and C(4,6) in the coordinate plane. The triangle will be reflected over the x-axis an

k0ka [10]

You should know that you can predict changes in coordinates after translations without a graph or anything like that.

(x, y) reflected over the x axis = (x, -y)
(x, y) reflected over the y axis = (-x, y)
(x, y) rotated 90 degrees around the origin = (y, -x)
(x, y) rotated 180 degrees around the origin = (-x, -y)
(x, y) rotated 270 degrees around the origin - (-x, y)

So here's our set of points.
A(1, 2), B(4, 6), C(4, 6)

Here's those points reflected over the x axis.
A'(1, -2), B'(4, -6), C'(4, -6)

And here's those points rotated 180° around the origin.
A''(2, -1), B''(6, -4), C''(6, -4)

I think you made a mistake writing down the question, though, because B and C are the same yet you say ABC forms a triangle. You should be able to go through this process with whatever the coordinate was supposed to be.

4 0

3 years ago

Help! Can anyone Simplify this for me

Tcecarenko [31]

64x $^{6}$ y $^{12}$

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3 years ago

Find the circumference, giving brainlies pls asap

zalisa [80]

Answer:

B) 12.6π ; 39.6

Step-by-step explanation:

Circumference:

C = 2πr

C = 2(3.14)(6.3)

C = 6.28(6.3)

C = 39.6

C = 2πr

C = 2π6.3

C = 12.6π

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3 years ago

Read 2 more answers

A triangle with sides 11m , 13m and 18m is a right triangle. A True B False

Julli [10]

$\bold{\huge{\pink{\underline{ Solution}}}}$

$\bold{\underline{ Given :-}}$

A triangle with sides 11m, 13m and 18m

$\bold{\underline{ To \: Find :-}}$

We have to check it whether it is right angled triangle or not?

$\bold{\underline{ Let's \: Begin :-}}$

$\sf{\red{ In \:right \:angled\ : triangle, }}$

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

We imply it in the given triangle ,

$\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}$