Answer:
5, 6, 9, 15
Also:
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2 x (n - 6)
(2 x n - 2 x 6)
(2n - 2 x 6)
2n - 12
<span>The square root of 121 is 11. The square toot of a^6 is a^3. Therefore 121a^6 can be expressed as (11a^3)^2, and 11a^3 is a monomial since it is a single term with nothing added or subtracted to it or from it. So 121a^6 as a squared monomial is (11a^3)^2.</span>
