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3 years ago

Plz help don't get it

Mathematics

1 answer:

MatroZZZ [7]3 years ago

8 0

Would help but I can't see the full page sorry man/woman

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What’s the answer no work needed Given f (x) = 5x2 and g(x) = 2x + 3, find f(g(-4))

Crazy boy [7]

Answer:

125

Step-by-step explanation:

Given

f(x) = 5x²

g(x) = 2x + 3

Now

g(-4) = 2 * (- 4) + 3

= - 8 + 3

= - 5

Also

f(g(-4)) = f( -5)

= 5 * ( -5)²

= 5 * 25

= 125

4 0

2 years ago

Helpppp plssss!! Show your work!! Thanks

Eduardwww [97]

Slope of a Line Passing through two points (x₁ , y₁) and (x₂ , y₂) is given by :

$\heartsuit\;\;Slope(m) = \frac{y_1 - y_2}{x_1 - x_2}$

Given Points are (-3 , 5) and (6 , -1)

here x₁ = -3 and x₂ = 6 and y₁ = 5 and y₂ = -1

$\heartsuit\;\;Slope(m) = \frac{5 + 1}{-3 - 6} = \frac{6}{-9} = \frac{-2}{3}$

Option D is the Answer

4 0

3 years ago

A school wishes to enclose its rectangular playground using 480 meters of fencing.

Harlamova29_29 [7]

Answer:

Part a) $A(x)=(-x^2+240x)\ m^2$

Part b) The side length x that give the maximum area is 120 meters

Part c) The maximum area is 14,400 square meters

Step-by-step explanation:

The picture of the question in the attached figure

Part a) Find a function that gives the area A(x) of the playground (in square meters) in terms of x

we know that

The perimeter of the rectangular playground is given by

$P=2(L+W)$

we have

$P=480\ m\\L=x\ m$

substitute

$480=2(x+W)$

solve for W

$240=x+W\\W=(240-x)\ m$

Find the area of the rectangular playground

The area is given by

$A=LW$

we have

$L=x\ m\\W=(240-x)\ m$

substitute

$A=x(240-x)\\A=-x^2+240x$

Convert to function notation

$A(x)=(-x^2+240x)\ m^2$

Part b) What side length x gives the maximum area that the playground can have?

we have

$A(x)=-x^2+240x$

This function represent a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the length that give the maximum area that the playground can have

Convert the quadratic equation into vertex form

$A(x)=-x^2+240x$

Factor -1

$A(x)=-(x^2-240x)$

Complete the square

$A(x)=-(x^2-240x+120^2)+120^2$

$A(x)=-(x^2-240x+14,400)+14,400$

$A(x)=-(x-120)^2+14,400$

The vertex is the point (120,14,400)

therefore

The side length x that give the maximum area is 120 meters

Part c) What is the maximum area that the playground can have?

we know that

The y-coordinate of the vertex represent the maximum area

The vertex is the point (120,14,400) -----> see part b)

therefore

The maximum area is 14,400 square meters

Verify

$x=120\ m$

$W=(240-120)=120\ m$

The playground is a square

$A=120^2=14,400\ m^2$

8 0

3 years ago

9 - 3 ( 5 - 4 x ) =============

tangare [24]

Answer:26x will be your answer

8 0

3 years ago

Read 2 more answers

jonathan ran 5 days this week. the most he ran in one day was 3.5 miles. write an inequality that shows the distance jonathan co

poizon [28]

Let m represent the number of miles this guy runs in a day.
He runs every day, so the minimum number of miles has to be greater than 0.
According to the problem statement, the max number of miles is 3.5 miles or less.

Translate this into a (symbolic) inequality.

4 0

2 years ago