Question

In triangle ABC, what is the measure of b if a = 6, C = 4,

Answer 1

Given:

In triangle ABC,  a = 6, c = 4, and B = 75°.

To find:

The measure of b.

Solution:

According to the Law of Cosine:

$b^2=a^2+c^2-2ac\cos B$

Substituting the given values in the above formula, we get

$b^2=(6)^2+(4)^2-2(6)(4)\cos (75^\circ)$

$b^2=36+16-48(0.2588)$

$b^2=52-12.4224$

$b^2=39.5776$

Taking square root on both sides, we get

$b=\sqrt{39.5776}$

$b=6.291073$

$b\approx 6.29$

The measure of side b is 6.29 units.

Therefore, the correct option is B.