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ki77a [65]
3 years ago
7

Find the possible values of c such that the line with equation y = 2x + c twice intersects the parabola with equation y = x^2 +

3x
Mathematics
2 answers:
11111nata11111 [884]3 years ago
8 0

Answer:

c > -¼

Step-by-step explanation:

x² + 3x = 2x + c

x² + x - c = 0

Since they intersect at 2 points,

B²-4AC > 0

(1)²-4(1)(-c) > 0

1 + 4c > 0

c > -¼

Maru [420]3 years ago
4 0

Answer:

C>-1/4

Step-by-step explanation:

Two have intersection it must be:

2x+c= x^2+3x, i.e,

x^2+x-c=0

Solution of its equation is:

x_{1,2}=\frac{-1+-\sqrt{1^2+4c}}{4c}

If we we want two solution we must have that:

1+4c>0

So c>-1/4.

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geniusboy [140]

1. keep the same

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A jar contains "q" quarters and "d" dimes. There are 7 coins in the jar and the total value of the coins is $1.00
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*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

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8 0
2 years ago
Read 2 more answers
What is the answer to this question plss and thank you
cluponka [151]

A defines the function

f(1) = - 8 ×( \frac{5}{2} )^{0} = - 8 × 1 = -8

f(2) = - 8 ×( \frac{5}{2}) ^{1} = - \frac{(8.5)}{2}= - 20

f(3) = - 8 ×( \frac{5}{2}) ^{2} = - 8 × \frac{25}{4} = - 50

f(4)= - 8 ×( \frac{5}{2}) ^{3} = - 8 × \frac{125}{8} = -125

f(5) = - 8 ×( \frac{5}{2}) ^{4} = - 8 × \frac{625}{16} = - \frac{625}{2}




4 0
3 years ago
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