Find the possible values of c such that the line with equation y = 2x + c twice intersects the parabola with equation y = x^2 +

Question

3 years ago

7

3x

2 answers:

11111nata11111 [884] · Answer 1 · 2022-04-04T10:59:30+03:00

8 0

Answer:

c > -¼

Step-by-step explanation:

x² + 3x = 2x + c

x² + x - c = 0

Since they intersect at 2 points,

B²-4AC > 0

(1)²-4(1)(-c) > 0

1 + 4c > 0

c > -¼

Maru [420] · Answer 2 · 2022-04-04T09:09:29+03:00

Maru [420]3 years ago

4 0

Answer:

C>-1/4

Step-by-step explanation:

Two have intersection it must be:

2x+c= x^2+3x, i.e,

x^2+x-c=0

Solution of its equation is:

$x_{1,2}=\frac{-1+-\sqrt{1^2+4c}}{4c}$

If we we want two solution we must have that:

1+4c>0

So c>-1/4.