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damaskus [11]
3 years ago
8

Helpppp

Mathematics
1 answer:
Mice21 [21]3 years ago
7 0

Answer:

18.33 - 21.99 mg

Step-by-step explanation:

BSA = √((68 kg)(70 in)(2.54 cm/in) / 3600) = 1.8326 m²

10(1.8326) = 18.33 mg

12(1.8326) = 21.99 mg

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Mark tranferred songs from his computer onto his portable music player. he transferred 2 6/7 songs in 1 2/3 minutes. How many so
SCORPION-xisa [38]
So basically; 
 2 6/7 : 1 2/3
as a top heavy fraction is...
20/7 : 5/3 
divide both sides by 5/3 to get x:1
12/7 : 1 
so he transfers 12/7 songs or as a mixed fraction 1 5/7 
3 0
3 years ago
Round 2.56×0.03 to the nearest hundredth
Arlecino [84]
2.56 times 0.03 is 0.0768 then round to hundredth is 0.08 i think 
4 0
4 years ago
Select the correct answer.
Ganezh [65]

Answer:

C. 6x(x² + 4x - 12)

Step-by-step explanation:

Factor 6x^{2} out of 6x^{4}

<em> </em>6x^{2}<em> (</em>x^{2}<em>) + </em>6x^{2}<em> + </em>24x^{3} - 72x^{2}<em />

<em> </em>6x^{2}<em> (</em>x^{2}<em>) + </em>6x^{2}<em> (</em>4x<em>) </em>-72x^{2}<em />

<em> </em>6x^{2}<em> (</em>x^{2}<em>) + </em>6x^{2}<em> (</em>4x<em>) + </em>6x^2 (-12)

6x^{2}<em>(</em>x^{2}<em> + </em>4x<em>) +  </em>6x^{2}<em> (-12)</em>

6x^{2}<em>(</em>x^{2}<em> + </em>4x<em> - 12 )</em>

8 0
3 years ago
Read 2 more answers
I really need help pls<br> Thanks
Orlov [11]
Would it be 0,-4 and 0,-2
7 0
3 years ago
Given: ABCD ∥gram, BK ⊥ AD , AB ⊥ BD AB=6, AK=3 Find: m∠A, BK, Area of ABCD
Morgarella [4.7K]

1. Consider right triangle ABK. In this triangle AB is the hypotenuse, BK and AK are legs. By the Pythagorean theorem,

AB^2=AK^2+BK^2,\\\\6^2=3^2+BK^2,\\\\BK^2=36-9=27,\\\\BK=3\sqrt{3}\ un.

2. Use the definition of \cos \angle A:

\cos \angle A=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{AK}{AB}=\dfrac{3}{6}=\dfrac{1}{2}.

Then m\angle A=60^{\circ}.

3. Consider right triangle ABD. In this triangle AD is the hypotenuse, AB and BD are legs. Since  m\angle A=60^{\circ}, then

m\angle BDA=180^{\circ}-90^{\circ}-60^{\circ}=30^{\circ}.

The leg that is opposite to the angle of 30° is half of the hypotenuse, so

AD=2AB=12\ un.

4. The area of parallelogram aBCD is

A_{ABCD}=AD\cdot BK=12\cdot 3\sqrt{3}=36\sqrt{3}\ sq. un.

3 0
3 years ago
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