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Roman55 [17]
3 years ago
13

How to view a webpage from an earlier date?

Computers and Technology
1 answer:
qaws [65]3 years ago
4 0
Http://archive.org/web/web.php 

I use this website
You might be interested in
Need this answered quickly, 40 PTS!
drek231 [11]

Hello,


Answer: In 1965, Gordon Moore noticed that the number of transistors per square inch on integrated circuits had doubled every year since their invention. Moore's law predicts that this trend will continue into the foreseeable future. ... The 18-month mark is the current definition of Moore's law.


Please read and you will have your answer!


If you did not love this answer let me know and I will try again.



7 0
3 years ago
Read 2 more answers
>What is the output of the following code:
ozzi

Answer:

Given code output is "786".

Explanation:

Code:

list1 = [ 'cyber', 786 , 2.23, 'square', 70.2 ]#defining a list list1 that holds value in parameter

print (list1[1] )#use a print method that prints list index value

In the given code a list "list1" is declared that holds value in it and in the next step a print method is declared that prints the first index value of the list.

5 0
3 years ago
Which expression correctly determines that String s1 comes before String s2 in lexicographical order
Assoli18 [71]

Options :

A.) s1 < s2

B.) s1 <= s2

C.) s1.compareTo(s2) == −1

D.) s2.compareTo(s1) < 0

E.) s1.compareTo(s2) < 0

Answer: E.) s1.compareTo(s2) < 0

Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.

If first string = s1 ; second string = s2

To compare s1 with s2, the format is ;

s1.compareTo(s2) ;

If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.

If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.

If both are s1 and s2 are the same, the output will be 0.

8 0
3 years ago
The _________ attack exploits the common use of a modular exponentiation algorithm in RSA encryption and decryption, but can be
coldgirl [10]

Answer:

The answer is "timing".

Explanation:

  • The time attack would be a security vulnerability that enables attackers that identify computer systems or network security issues by analyzing the period of the program's reaction to multiple levels.  
  • It is used in both RSA encryption and decryption of the modular exponentiation method but could be modified for just about any system not seem running in a fixed period.
6 0
3 years ago
Consider the following line of code: if (x &lt; 12 || (r – 3 &gt; 12)) Write three valid mutants of this ground string (based on
Nata [24]

Answer:

See explaination

Explanation:

Mutation Testing:

Mutation Testing is a type of software testing where we mutate (change) certain statements in the source code and check if the test cases are able to find the errors. It is a type of White Box Testing which is mainly used for Unit Testing. The changes in the mutant program are kept extremely small, so it does not affect the overall objective of the program.

We say a mutant is valid if it is syntactically correct. We say a mutant is useful if, in addition to being valid, its behavior differs from the behavior of the original program for no more than a small subset of program test cases.

VALID MUTANTS

1. if (x < 12 && (r – 3 > 12)) LOR

2. if (x < 12 || (r – 3 < 12)) ROR

3. if (x < 12 || (x – 3 < 12)) IVR

INVALID MUTANTS

1. if (x < 12 ||(r – 3 > 12) UPR

2. if (x < 12 (r – 3 < 12)) MLO

3. (x < 12 || (x – 3 < 12)) CSM

Note:

LOR: LOGICAL OPERATOR REPLACEMENT

ROR: RELATIONAL OPERATOR REPLACEMENT

IVR: INVALID VARIABLE REPLACEMENT

UPR: UNBALENCED PARANTHISIS REPLACEMENT

MLO: MISSING LOGICAL OPERATOR REPLACEMENT

CSM: CONTROL OPERATOR MISSING REPLACEMEN

4 0
3 years ago
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