Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
Answer:
Know what the code should do
Answer:
C. 7200 bps.
Explanation:
In networking, transmission lines or connectors and ports operates at a specific speed based on the port type and the cable or medium of transmission.
Baud rate is a concept in digital information technology that defines the rate of symbol per channel during transmission. The bit or data rate is the number of bits transfered in a link per second.
The relationship between baud rate and bit rate is;
Bit rate = baud rate x number of symbol bit level
To get the bit rate of a 2400 baud signal with symbol level = 8 = 2^3
Bit rate = 2400 x 3. = 7200 bps.
Usually that means a physical connection - so either a loose or faulty ethernet cord.
