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tino4ka555 [31]
3 years ago
5

How do you use bold text?

Computers and Technology
2 answers:
taurus [48]3 years ago
8 0

Answer:

Android: Tap and hold the text you're entering in the text field, then choose Bold, Italic, or More . Tap More to choose Strikethrough or Monospace. iPhone: Tap the text you're entering in the text field > Select or Select All > B_I_U. Then, choose Bold, Italic, Strikethrough, or Monospace.

Explanation:

Mrac [35]3 years ago
7 0

Answer:

Depends on what site or app you're asking about. But usually you just select the word or sentence you want to bold using your cursor, then the sentences will be highlighted blue and then click B. Most websites have the bold function denoted with a B so you can easily understand that the button is used for making a word or sentences bold.

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Gelneren [198K]
A world that uses technology.
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3 years ago
Write down the appropriate technical term of following statements.​
MrRa [10]

Answer:

it is not seeing full. please give full

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What type of hardware enables users to interact with a computer? Check all that apply. the CPU the hard disk drive the keyboard
valentina_108 [34]

Answer:

the keyboard

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Explanation:

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6 0
4 years ago
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Which of the following is not an operating system? Linux Nexus Mac OS Windows
laila [671]
I belive Nexus is not a Operating system, I am not a pro at knowing all of the operating system.
7 0
3 years ago
A computer has a cache and main memory. 20 ns are required to reference a word that is in the cache. If the word is in main memo
Alecsey [184]

Answer:

T_{average} =12026ns

Explanation:

Given Information:

T_{cache}=20 ns

T_{main}=60ns

T_{disk} =12ms=12,000,000ns

hit_{cache} =0.9

miss_{cache} =1-0.9=0.10

hit_{main} =0.99

miss_{main} =1-0.99=0.01

There are 3 possible cases

1. Location of reference word is in cache

T_{cache}*hit_{cache} =20*0.9=18ns

2. Location of reference word is not in cache but in main memory

(T_{cache}+T_{main})*(miss_{cache}*hit_{main}) =(20+60)*(0.10*0.99)=7.92ns

3. Location of reference word is neither in cache nor in main memory

(T_{cache}+T_{main}+T_{disk})*(miss_{cache}*miss_{main})

(20+60+12,000,000)*(0.10*0.01)=12000.08 ns

The average time required to access a referenced word on this system is simply the sum of above 3 cases

T_{average} =18+7.92+12000.08=12026ns

5 0
4 years ago
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