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yarga [219]
4 years ago
6

Please help with the question no. 5 and 7 please help ​

Computers and Technology
1 answer:
mafiozo [28]4 years ago
5 0

Answers For question one... Picture I and 2

Question 2...picture 3

Question 3.. Picture 4

Explanation:

Hope it is the best answer.. Any questions regarding this answer... You can ask me✌️

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What type of tool displays preferred content from several sources, such as RSS feeds, social networking tools, and social news w
zheka24 [161]

Answer:

Aggregator

Explanation:

The answer to this question is an aggregator. An aggregator us a tool that is useful for discovering content as well as acting as a content curator from different social media outlets and then puts them into one feed. This feed could then be shown across all channels. The feed after it has Ben combined can be shown on a website.

5 0
3 years ago
I thought brainly was better than this...
olasank [31]

Answer:

I know right! i make sure i know the answer before i reply. it should ONLY let you answer with a real answer. most of the time they dont even do anything about it :( i agree so much with this comment.

also im pretty sure with the A+ students its only with brainly+

4 0
3 years ago
Read 2 more answers
You can calculate the surface area of a cube if you know the length of an edge. Write a program that takes the length of an edge
Ivenika [448]

Answer:

Program in Python:

edge = float(input("Edge Length: "))

area = 6 * edge**2

print("Surface Area: "+str(area))

Explanation:

This line prompts the user for the length of the edge

edge = float(input("Edge Length: "))

This calculates the surface area using Area = 6a^2

area = 6 * edge**2

This prints the calculated surface area

print("Surface Area: "+str(area))

<em>This solution was implemented in Python</em>

8 0
3 years ago
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Kevin wants to distribute his research paper to four of his friends. Which option will allow him to make four printouts so that
Anna [14]
I suppose you are using Microsoft Office, whichever the version is, just press Control+P to print the pages, select how many copies you want, select the size of paper and click on Print. Do not change any other setting.
3 0
3 years ago
write a program to evaluate the following postfix expression. the value of each variable must be asked from the user during the
ikadub [295]

In this exercise we have to use the knowledge of computational language in C++ to write a code that program to evaluate the following postfix expression. the value of each variable must be asked from the user during the execution time.

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// CREATED A </em><em>CLASS </em><em>STACK</em>

<em>class Stack</em>

<em>{</em>

<em>public:</em>

<em> int top;</em>

<em> unsigned sz;</em>

<em> int* ar;</em>

<em>};</em>

<em>// VARIOUS STACK </em><em>FUNCTIONS</em>

<em>Stack* makeStack( unsigned sz )</em>

<em>{</em>

<em> Stack* stack = new Stack();</em>

<em> // BASE </em><em>CONDITION</em>

<em> if (!stack) return NULL;</em>

<em> stack->top = -1;</em>

<em> stack->sz = sz;</em>

<em> stack->ar = new int[(stack->sz * sizeof(int))];</em>

<em> if (!stack->ar) return NULL;</em>

<em> // RETURNING THE STACK</em>

<em> return stack;</em>

<em>}</em>

<em>// CHECKING IF THE STACK IS </em><em>EMPTY</em>

<em>int isEmpty(Stack* stack)</em>

<em>{</em>

<em> return stack->top == -1 ;</em>

<em>}</em>

<em>// CHECKING THE TOP OF THE STACK</em>

<em>int whatAtTop(Stack* stack)</em>

<em>{</em>

<em> return stack->ar[stack->top];</em>

<em>}</em>

<em>// </em><em>POPPING </em><em>OUT OF A STACK</em>

<em>int pop(Stack* stack)</em>

<em>{</em>

<em> if (!isEmpty(stack))</em>

<em>  return stack->ar[stack->top--] ;</em>

<em> return '$';</em>

<em>}</em>

<em>// PUSHING IN THE STACK</em>

<em>void push(Stack* stack, int op)</em>

<em>{</em>

<em> stack->ar[++stack->top] = op;</em>

<em>}</em>

<em>// EVALUATING </em><em>POSTFIX </em><em>STARTS HERE</em>

<em>int postfixEvaluator(string res)</em>

<em>{</em>

<em> // CREATING STACK</em>

<em> Stack* stack = makeStack(res.length());</em>

<em> int i;</em>

<em> // BASE </em><em>CONDITION</em>

<em> if (!stack) return -1;</em>

<em> for (i = 0; res[i]; ++i)</em>

<em> {</em>

<em>  // CHECK FOR SPACES</em>

<em>  if (res[i] == ' ')continue;</em>

<em>  // CHECK FOR THE DIGIT</em>

<em>  else if (isdigit(res[i]))</em>

<em>  {</em>

<em>   int N = 0;</em>

<em>   // EXTRACT THE </em><em>NUMBER </em><em>OUT OF STACK</em>

<em>   while (isdigit(res[i]))</em>

<em>   {</em>

<em>    N = N * 10 + (int)(res[i] - '0');</em>

<em>    i++;</em>

<em>   }</em>

<em>   i--;</em>

<em>   // </em><em>PUSH </em><em>THE NUMBER IN STACK</em>

<em>   push(stack, N);</em>

<em>  }</em>

<em>  // POPPING AND </em><em>ARITHMETIC </em><em>OPERATIONS</em>

<em>  else</em>

<em>  {</em>

<em>   int pos1 = pop(stack);</em>

<em>   int pos2 = pop(stack);</em>

<em>   switch (res[i])</em>

<em>   {</em>

<em>   case '+': push(stack, pos2 + pos1); break;</em>

<em>   case '-': push(stack, pos2 - pos1); break;</em>

<em>   case '*': push(stack, pos2 * pos1); break;</em>

<em>   case '/': push(stack, pos2 / pos1); break;</em>

<em>   }</em>

<em>  }</em>

<em> }</em>

<em> return pop(stack);</em>

<em>}</em>

<em>// MAIN CODE</em>

<em>int main()</em>

<em>{</em>

<em> string tes;</em>

<em> getline(cin, tes);</em>

<em> string tmp = "";</em>

<em> string res = "";</em>

<em> for (int i = 0; i < tes.length(); i++) {</em>

<em>  if (tes[i] <= 'z' and tes[i] >= 'a') {</em>

<em>   tmp += tes[i];</em>

<em>  } else if (tes[i] == ' ' and (tes[i - 1] <= 'z' and tes[i - 1] >= 'a')) {</em>

<em>   cout << "Enter the value of " << tmp << ": ";</em>

<em>   int x; cin >> x;</em>

<em>   res += (to_string(x));</em>

<em>   res += ' ';</em>

<em>   tmp = "";</em>

<em>  } else {</em>

<em>   res += tes[i];</em>

<em>  }</em>

<em> }</em>

<em> cout << "\nThe postfix expression is : " << res;</em>

<em> cout << "\nThe result is : " << postfixEvaluator(res);</em>

<em> return 0;</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

8 0
1 year ago
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