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lisabon 2012 [21]
3 years ago
12

A soccer game is 90 minutes long. 36 minutes have passed.

Mathematics
1 answer:
laila [671]3 years ago
5 0

Answer: 40%

Step-by-step explanation:

The answer is 40%. 36/90 is 0.4 in decimal form,and since percentages are out of a hundred, the answer is 40%

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Sketch the graph of y = (x + 3)2 – 4 and identify the axis of symmetry.
Sloan [31]

Answer: Thought I’d return the favor and help u with this question! But anyways, the axis of symmetry is at x = -3.

Explanatio: This can be found by looking at the basic form of vertex form:

y = (x - h)^2 + k

In this basic form the vertex is (h, k). By looking at what is plugged into the equation, it is clear that h = -3 and k = -4. This means the vertex is at (-3, -4).

It is a fact that the axis of symmetry is a vertical line of x = (vertex value of x). So we can determine that the axis of symmetry is at x = -3

i hope this helps u

4 0
3 years ago
What is the effect on the area of a rectangle if the dimensions are doubled?
alisha [4.7K]
Let x be the length and y be the width of a rectangle.
Area = xy

When x and y are doubled
Length = 2x and Width = 2y
Area = 2x x 2y
Area = 4xy

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Answer: When the dimension is doubled, the area is 4 times the original.
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8 0
3 years ago
Another question I need help with
mote1985 [20]

Answer:

8 forks for every 1 table I hope this helped u :))

Step-by-step explanation:

5 0
3 years ago
Hurry please!<br> Find the slope <br> A. -3/5<br> B. 3/5<br> C. -5/3<br> D. 5/3
IceJOKER [234]

Answer:

\frac{5}{3} should be correct!

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t &gt; 0 y(t) =
Helen [10]

For the ODE

ty'+2y=\sin t

multiply both sides by <em>t</em> so that the left side can be condensed into the derivative of a product:

t^2y'+2ty=t\sin t

\implies(t^2y)'=t\sin t

Integrate both sides with respect to <em>t</em> :

t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C

Divide both sides by t^2 to solve for <em>y</em> :

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}

Now use the initial condition to solve for <em>C</em> :

y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}

\implies9=\dfrac4{\pi^2}(1+C)

\implies C=\dfrac{9\pi^2}4-1

So the particular solution to the IVP is

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}

or

y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}

6 0
3 years ago
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