Answer:
The answer is 100
Step-by-step explanation:
Answer:
(a) 
(b) 
(c) 
Step-by-step explanation:
We have given velocity as function of t 
Acceleration is equation rate if change of velocity with respect to time
So 
(a) Acceleration at t = 5 sec

(b) Acceleration at t = 10 sec

(c) Acceleration at t = 20 sec

Answer:
B, it's the only plausible one. A is wrong because the value would be above 180°
Answer:
the answer is b:-6
Step-by-step explanation:
hoped I helped:)
V = 4/3πr³
V = 4/3(3.14)(14)³
V = 4/3(3.14)(2744)
V = 4/3(8616.16)
V = 11488.21333cm³