Ms. PB is pushing Mr. Rigney in a wheelchair with a force of 10 N East, while Mr. Rigney is using his arms to

Physics

1 answer:

kumpel [21]3 years ago

4 0

The net force is 6 N East

Explanation:

First of all, we start by noticing that all the forces act along the direction East-West, so we can simply find the net force by using algebraic addition.

In order to find the net force on the wheelchair, we need to define a positive direction and write down all the force with the proper sign.

Let's choose East as positive direction. Therefore, we have the following forces:

$F_1 = +10 N$ (east), the force applied by Ms. PB

$F_2 = +5 N$ (east), the force applied by Mr. Rigney

$F_f = -2 N$ (west), the frictional force, acting in the opposite direction

$F_r = -7 N$ (west), the air resistance, acting in the opposite direction

Taking into account the correct signs, we can now find the net force on the wheelchair:

$F=F_1+F_2+F_f+F_r = +10 + 5 +(-2) + (-7) = +6 N$

And the positive sign tells us that the direction of the net force is East.

Learn more about forces:

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A 0.2 kg hockey park is sliding along the eyes with an initial velocity of -10 m/s when a player strikes it with his stick, caus

babunello [35]

Answer:

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.

Explanation:

The Impulse Theorem states that the impulse experimented by the hockey park is equal to the vectorial change in its linear momentum, that is:

$I = m\cdot (\vec{v}_{2} - \vec{v_{1}})$ (1)

Where:

$I$ - Impulse, in kilogram-meters per second.

$m$ - Mass, in kilograms.

$\vec{v_{1}}$ - Initial velocity of the hockey park, in meters per second.

$\vec{v_{2}}$ - Final velocity of the hockey park, in meters per second.

If we know that $m = 0.2\,kg$ , $\vec{v}_{1} = -10\,\hat{i}\,\left[\frac{m}{s}\right]$ and $\vec {v_{2}} = 25\,\hat{i}\,\left[\frac{m}{s} \right]$ , then the impulse applied by the stick to the park is approximately: