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STALIN [3.7K]
3 years ago
5

What is another name for Angle 1? Line segments J L and L M combine to form an angle. Line segment L K comes out of the angle to

form 2 angles. Angle J L K is 1 and angle K L M is 2. Angle J L K Angle L K J Angle K L M Angle L K M
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
3 0

Answer: The answer is the first one, angle JLK

Step-by-step explanation:

Tems11 [23]3 years ago
3 0

Answer: A / JLK

Step-by-step explanation:

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The populations of Cities A and B are 1.6 x 10^5 and 1,070,000​, respectively. The population of City C is twice the population
Semenov [28]

Answer:

13.375 times

Step-by-step explanation:

1,070,000 times 2=2,140,000. 2,140,000 divided by 160,000=13.375.

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What is the denominator of 13 over 107 in simplest form
Pavel [41]

13/107 can't be simplified but in decimal form it would be 0.121495327103.


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In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

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3 years ago
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omeli [17]
Okay so.
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B is 4.95
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What is the distance between the points H(-5,9) and J(1,6)?
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Answer:The answer would be b

Step-by-step explanation:

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3 years ago
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