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saw5 [17]
3 years ago
14

Maria has a 30% coupon for her $60 dollar jeans, what is the new price

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
3 0

Answer:

$42

Step-by-step explanation:

Since she has a 30% coupon, the new price of the jeans will be 30% of the original price subtracted from the original price

Original price = $60

Therefore

30% of $60

Make 30% a decimal

30/100 x $60

0.3 x $60 = $18

New price = $60 - $18

= $42

The new price for the jeans is $42

Luba_88 [7]3 years ago
3 0

Answer: $42

Step-by-step explanation:

Since she has a 30% coupon, the new price of the jeans will be 30% of the original price subtracted from the original price

Original price = $60

You need to take out 30% of $60

Make 30% a decimal

.30 x $60

0.3 x $60 = $18

Now subtract the money she saved from the initial price to get her new price

New price = $60 - $18 = $42

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Why is the lcm of two numbers never less than the larger number?
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This involves a bit of logic in thinking about what LCM actually means.

LCM is the least common multiple. A common multiple is a multiple shared by two or more numbers. And by multiple, we mean some number multiplied by successive integers; this set contains multiples of 5 {5, 10, 15, 20, 25...}. You can see that the least (or lowest) common multiple is the lowest multiple shared by two numbers. Like for 6 and 9, you have {6, 12, 18, 24...} and {9, 18...}, so LCM(6,9) = 18. 

Now, if an LCM must be shared by both numbers, and to get a multiple of the largest number, you have to multiply by an integer greater than or equal to 1, then the LCM of two numbers can never be less than the larger of the twi numbers. Generally, if x and y are positive real numbers, and x is greater than y, LCM(x,y)  \leq x. 
4 0
4 years ago
a bicycle store costs 3000$ per month to operate, the store pays an average of $60 per bike. the average selling price of each b
lara31 [8.8K]

Answer:

they must sell 75 bikes each month to pay the $3000 they would need to sell 76 bikes to get over $3000. so... 76 x 40= $3040

Step-by-step explanation:

$100 - $60 = $40

$3000/40 = 75

6 0
3 years ago
What percent of the 2019 world population lives in Canada? Round the percentage to three decimal places.
dimaraw [331]

0.486 % of world population lives in canada

<em><u>Solution:</u></em>

From given,

World population = 7691 million

Canada population = 37.4 million

We have to find the percent of world population lives in canada

Let "x" be the percent of world population lives in canada

Therefore, from question,

x % of world population = canada population

x % of 7691 = 37.4

<em><u>Solve the above equation for "x"</u></em>

x \% \times 7691 = 37.4\\\\\frac{x}{100} \times 7691 = 37.4\\\\7691x = 3740\\\\Divide\ both\ sides\ by\ 7691\\\\x = \frac{3740}{7691}\\\\x = 0.486

Thus 0.486 % of world population lives in canada

8 0
3 years ago
Find a 90% confidence interval for the mean of all tree ring dates from this archaeological site. (round your answers to the nea
creativ13 [48]
Given a table below which gives the years in A.D. for an archaeological excavation site using the method of tree ring dating:

\begin{tabular}&#10;{|c|c|c|c|c|c|c|c|c|}&#10;1229&1292&1187&1257&1268&1316&1275& 1317&1275&#10;\end{tabular}

Part A:

The sample mean is given by:

\bar{x}= \frac{1229+1292+1187+1257+1268+1316+1275+ 1317+1275}{9} \\  \\  = \frac{11416}{9} =1268

Therefore, the sample mean is 1268.



Part B:

We calculate the sample standard deviation as follows:

s= \frac{1}{9-1} \left(\sqrt{(1229-1268)^2+(1292-1268)^2+(1187-1268)^2+(1257-1268)^2+(1268-1268)^2+(1316-1268)^2+(1275-1268)^2+(1317-1268)^2+(1275-1268)^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{(-39)^2+24^2+(-81)^2+(-11)^2+0^2+48^2+7^2+49^2+7^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{1521+576+6561+121+2304+49+2401+49}\right)\\ \\ = \frac{1}{8}\left(\sqrt{13,582}\right)\\ \\ = \frac{1}{8}(116.54)=14.57\approx15



Part C:

The 90% confidence interval is given by:

90\% \ C. \ I.=1268\pm1.65\left(\frac{15}{\sqrt{9}}\right) \\  \\ =1268\pm\left(\frac{15}{3}\right)=1268\pm5 \\  \\ =(1268-5, \ 1268+5)=(1263, \ 1273)
8 0
3 years ago
Listed are 32 ages for Academy Award winning best actors in order from smallest to largest. (Round your answers to the nearest w
Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

The ages for Academy Award winning best actors in order from smallest to largest are

18; 18; 21; 22; 25; 26; 27; 29; 30; 31; 31; 33; 36; 37; 37; 41; 42; 47; 52; 55; 57; 58; 62; 64; 67; 69; 71; 72; 73; 74; 76; 77

The total number of terms, n is 32

31℅ of 32 = 31/100 × 32 = 0.31 × 32 = 9.92. It is approximately 10

Counting from left to right, the 10th term is 31. This means that the 31st percentile is 31

8 0
4 years ago
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