The slope intercept form of the line whose points are (1,5) and (-2,-4) is y=3x+2.
Given two points of a line (1,5) and (-2,-4).
We have to form an equation in slop intercept form.
Equation is relationship between two or more variables which are expressed in equal to form.Equations of two variables looks like ax+by=c.
Point slope form of an equation is y=x+mc where m is slope of the line.
From two points the formula of equation is as under:
(y-
)=
*(x-
)
where
are the points.
Putting the values of
=1,
=-2,
=5 and
=-4.
y-5=(-4-5/-2-1)*(x-1)
y-5=-9/-3*(x-1)
y-5=3(x-1)
y-5=3x-3
y=3x-3+5
y=3x+2
Hence the slope intercept form of the line having points (1,5)(-2,-4) is y=3x+2.
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(2x³ - 5x² + 8)(x + 3) = ?
First step is to distribute.
2x^4 + 6x³ - 5x³ - 15x² + 8x + 24
Now combine like terms.
2x^4 + x³ - 15x² + 8x + 24
This is your answer, since you can't simplify any further or solve it without some more information.
The 3rd selection is appropriate.
.. 5b +1 = a = 3b +5
by the transitive property of equality,
.. 5b +1 = 3b +5
SOH-CAH-TOA
sin=opp/hyp
cos=adj/hyp
tan=opp/adj
1. Sin c=opp/hyp 2. tan=opp/adj 3. sin=opp/hyp
sin c=8/17 tan38°=x/16 sin38=18/x
x=18/sin38; x=29.236846