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4 years ago

Which of the following obtains data from a subset of a population to evaluate traits of the population?

Mathematics

1 answer:

andrey2020 [161]4 years ago

4 0

Is A across sectial survey

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ANSWER ASAP PLEASE Which of the following are functions? Pick more than one

ikadub [295]

Answer:

abc

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which of the following is a logical conclusion to the conditional statements

stellarik [79]

Answer:

Step-by-step explanation:

If I text him now, then I will catch him before he gets home.

If I catch him before he gets home, then he will meet me in

time.

If a then b, If b then c

Combine both conditional statements by cancelling out the middle man, which is "I will catch him before he gets home."

So you get, "If i text him now, he will meet me in time"

7 0

2 years ago

F(x) = (64/63)(1/2)x, x = 1,2,3,...6. determine the requested values: round your answers to three decimal places (e.g. 98.765).

AleksandrR [38]

Calculator can help you

6 0

3 years ago

In a previous exercise we formulated a model for learning in the form of the differential equation dP dt = k(M − P) where P(t) m

GalinKa [24]

Answer:

$\frac{dP}{M-P}= kdt$

And we can integrate both sides of the equation using the following substitution:

$u= M-P, du =-dP$

And replacing we got:

$\int -\frac{du}{u} = kt +C$

$-ln (u)= kt+c$

If we multiply both sides by -1 we got:

$ln (u ) = -kt -c$

$ln (M-P) = -kt -c$

And using exponential in both sides of the equation we got:

$M-P = e^{-kt} e^{-c}$

And solving for P we got:

$P(t) = M- e^{-kt}e^{-c}$

And replacing $P_o =e^{-c}$ we got:

$P(t) = M - P_o e^{-kt}$

We can use the condition $P(0)=0$ and we got:

$0 = M -P_o e^0$

And we see that $M = P_o$ and replacing we got:

$P= M(1- e^{-kt})$

Step-by-step explanation:

For this case we aasume the following differential equation:

$\frac{dP}{dt}= k(M-P)$

Is a separable differential equation so we can do the following procedure:

$\frac{dP}{M-P}= kdt$

And we can integrate both sides of the equation using the following substitution:

$u= M-P, du =-dP$

And replacing we got:

$\int -\frac{du}{u} = kt +C$

$-ln (u)= kt+c$

If we multiply both sides by -1 we got:

$ln (u ) = -kt -c$

$ln (M-P) = -kt -c$

And using exponential in both sides of the equation we got:

$M-P = e^{-kt} e^{-c}$

And solving for P we got:

$P(t) = M- e^{-kt}e^{-c}$

And replacing $P_o =e^{-c}$ we got:

$P(t) = M - P_o e^{-kt}$

We can use the condition $P(0)=0$ and we got:

$0 = M -P_o e^0$

And we see that $M = P_o$ and replacing we got:

$P= M(1- e^{-kt})$

8 0

3 years ago

-3 + (- 1/6) what is ansewe help asap

vichka [17]

Answer:

-3.16666666667

Step-by-step explanation:

3 0

3 years ago