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Artyom0805 [142]
2 years ago
10

Which of the four representations are incorrect?

Mathematics
2 answers:
ruslelena [56]2 years ago
8 0
The second one is correct because it does not match the rest
Schach [20]2 years ago
4 0
Y=6x + 27 isn’t right
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I NEED HELP PLEASE ! :(
denis-greek [22]

Answer:

4

Step-by-step explanation

because 256 is root of  4 raised to 4

so 4 root 4 is to 4 which is = to 4

hope it helped u i am new on brainly so counldnt write properly

if it helped u plzzz mark as brainliest

3 0
3 years ago
1 - 3x = 3x + 1 solve for x
lakkis [162]

Answer: x = 0

Step-by-step explanation:

1 - 3x = 3x + 1

then add 3x on both sides

1 = 6x + 1

then subtract 1 on both sides

0 = 6x

then divide by 6 on both sides

0 = x

so x = 0

3 0
2 years ago
Read 2 more answers
Domain and range<br><br> O Function<br> O Not a function
Elodia [21]

Answer:

Radiation 1- Function

Radiation 2- Not a function

Radiation 3- function

Radiation 4- function

8 0
2 years ago
Read 2 more answers
Write the partial fraction decomposition fro the ration expression below
zlopas [31]
\dfrac{5x-2}{(x-1)^2}=\dfrac a{x-1}+\dfrac b{(x-1)^2}
5x-2=a(x-1)+b

Since 5x-2=5x-5+3=5(x-1)+3, it follows that a=5 and b=3, so

\dfrac{5x-2}{(x-1)^2}=\dfrac5{x-1}+\dfrac3{(x-1)^2}

\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac{x^3+x+x+2}{x^2(x^2+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac{cx+d}{x^2+1}
x^3+x^2+x+2=ax(x^2+1)+b(x^2+1)+(cx+d)x^2
x^3+x^2+x+2=(a+c)x^3+(b+d)x^2+ax+b

When x=0, you find that b=2. It's also clear that a=1. So the remaining constants must be 1+c=1\implies c=0 and 2+d=1\implies d=-1, and so you get

\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac1x+\dfrac2{x^2}-\dfrac1{x^2+1}
6 0
3 years ago
HELP ILL GIVE BRAINLIEST what’s the shape of the base?
Ket [755]

Answer:

the shape of the base is a rectangle, and the area of that rectangle is 160

Step-by-step explanation:

3 0
2 years ago
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