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2 years ago

Which of the four representations are incorrect?

Mathematics

2 answers:

ruslelena [56]2 years ago

8 0

The second one is correct because it does not match the rest

Schach [20]2 years ago

4 0

Y=6x + 27 isn’t right

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I NEED HELP PLEASE ! :(

denis-greek [22]

Answer:

Step-by-step explanation

because 256 is root of 4 raised to 4

so 4 root 4 is to 4 which is = to 4

hope it helped u i am new on brainly so counldnt write properly

if it helped u plzzz mark as brainliest

3 0

3 years ago

1 - 3x = 3x + 1 solve for x

lakkis [162]

Answer: x = 0

Step-by-step explanation:

1 - 3x = 3x + 1

then add 3x on both sides

1 = 6x + 1

then subtract 1 on both sides

0 = 6x

then divide by 6 on both sides

0 = x

so x = 0

3 0

2 years ago

Read 2 more answers

Domain and range<br><br> O Function<br> O Not a function

Elodia [21]

Answer:

Radiation 1- Function

Radiation 2- Not a function

Radiation 3- function

Radiation 4- function

8 0

2 years ago

Read 2 more answers

Write the partial fraction decomposition fro the ration expression below

zlopas [31]

$\dfrac{5x-2}{(x-1)^2}=\dfrac a{x-1}+\dfrac b{(x-1)^2}$
$5x-2=a(x-1)+b$

Since $5x-2=5x-5+3=5(x-1)+3$ , it follows that $a=5$ and $b=3$ , so

$\dfrac{5x-2}{(x-1)^2}=\dfrac5{x-1}+\dfrac3{(x-1)^2}$

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac{x^3+x+x+2}{x^2(x^2+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac{cx+d}{x^2+1}$
$x^3+x^2+x+2=ax(x^2+1)+b(x^2+1)+(cx+d)x^2$
$x^3+x^2+x+2=(a+c)x^3+(b+d)x^2+ax+b$

When $x=0$ , you find that $b=2$ . It's also clear that $a=1$ . So the remaining constants must be $1+c=1\implies c=0$ and $2+d=1\implies d=-1$ , and so you get

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac1x+\dfrac2{x^2}-\dfrac1{x^2+1}$

6 0

3 years ago

HELP ILL GIVE BRAINLIEST what’s the shape of the base?

Ket [755]

Answer:

the shape of the base is a rectangle, and the area of that rectangle is 160

Step-by-step explanation:

3 0

2 years ago