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2 years ago

7

Can I please get help with this question? thanks in advance.

1 answer:

dlinn [17]2 years ago

4 0

so it would be 6 times a number so 6a (a is the non-known number) than + 8 and same with a is it is 6a+8b

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What is the answer to<br> 56 is 28% of

klio [65]

In mathematics, 'is' would be the equal sign. And 'of' would be the multiplcation sign. The missing number would be any variable.

56 is 28% of a number would be translated algebraically to:

$56 = \frac{28}{100} \times x$

Solving for x, we get:

$56 = \frac{28}{100} \times x$

Divide 28 on both sides

$2 = \frac{x}{100}$

Multiply 100 on both sides

$x = 200$

56 is 28% of 200

5 0

3 years ago

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2r2 + 3s3 − r2 + 4t2 − r2 if r = −2, s = −3, and t = 5

Strike441 [17]

<span>2r2 + 3s3 − r2 + 4t2 − r2
</span>
= 19

6 0

3 years ago

Nana76 [90]

Answer:

it looks like its negative 2

5 0

2 years ago

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Find an equation of the sphere containing all surface points P = (x, y, z) such that the distance from P to A(−3, 6, 3) is "twic

Marina86 [1]

Answer:

Equation of Sphere = $x^{2}$ + $y^{2}$ + $z^{2}$ - 18x - 4/3y +10z + 142/3 = 0

Step-by-step explanation:

Data Given:

P = (x,y,z)

Distance from P to A (-3,6,3) = Twice the distance from P to B(6,2,-3)

Solution:

Find the equation of the sphere:

It is given that:

PA = 2PB

Squaring both sides:

$(PA)^{2} = (2PB)^{2}$

$(PA)^{2} = 4 (PB)^{2}$

$(x - (-3))^{2}$ + $(y - 6)^{2}$ + $(z-3)^{2}$ = 4 x $(x-6)^{2}$ + $(y-2)^{2}$ + $(z-(-3))^{2}$

Solving the above equation:

$(x + 3))^{2}$ + $(y - 6)^{2}$ + $(z-3)^{2}$ = 4 x { $(x-6)^{2}$ + $(y-2)^{2}$ + $(z + 3))^{2}$ }

$x^{2}$ + 9 + 6x + $y^{2}$ + 36 - 12y + $z^{2}$ + 9 - 6z = 4 { $x^{2}$ + 36 - 12x + $y^{2}$ + 4 - 4y + $z^{2}$ + 9 + 6z}

$x^{2}$ + 9 + 6x + $y^{2}$ + 36 - 12y + $z^{2}$ + 9 - 6z = 4 $x^{2}$ + 144 - 48x +4 $y^{2}$ + 16 - 16y + 4 $z^{2}$ + 36 + 24z

Putting the right hand side = 0 and solving the equation:

$x^{2}$ - 4 $x^{2}$ + $y^{2}$ - 4 $y^{2}$ + $z^{2}$ - 4 $z^{2}$ + 6x + 48x - 12y +16y -6z - 24z + 9 + 36 + 9 -144 - 16 - 36 = 0

-3 $x^{2}$ - 3 $y^{2}$ -3 $z^{2}$ + 54x + 4y -30z -142 = 0

Taking (-) common

- ( 3 $x^{2}$ + 3 $y^{2}$ + 3 $z^{2}$ - 54x - 4y +30z + 142) = 0

3 $x^{2}$ + 3 $y^{2}$ + 3 $z^{2}$ - 54x - 4y +30z + 142 = 0

dividing the whole equation by 3

$x^{2}$ + $y^{2}$ + $z^{2}$ - 54/3x - 4/3y +30/3z + 142/3 = 0

$x^{2}$ + $y^{2}$ + $z^{2}$ - 54/3x - 4/3y +30/3z + 142/3 = 0

$x^{2}$ + $y^{2}$ + $z^{2}$ - 18x - 4/3y +10z + 142/3 = 0

7 0

3 years ago

The system of equations y = negative one-half x + 4 and y = 2x – 1 is shown on the graph below. According to the graph, what is

dimaraw [331]

Answer:

(2, 3 )

Step-by-step explanation:

The solution to a system of equations given graphically is at the point of intersection of the 2 lines.

point of intersection = (2, 3 ) ← is the solution

8 0

3 years ago