Calculate the monthly payment of the following mortgages:

A can of juice has a diameter of 6.6 centimeters and a height of 12.1 centimeters and a height of3 what is the volume of the sto

andreyandreev [35.5K]

Answer:

Volume of the juice can = $413.75cm^3$

Step-by-step explanation:

Given:

$Diameter= 6.6 cm$

$Radius= 6.6/2=3.3 cm$

$Height= 12.1 cm$

Volume of a cylinder= $\pi *r^2*h$

: $\pi =\frac{22}{7} =3.14$

Volume of the cylindrical Juice can = $3.14*3.3*3.3*12.1$

= $413.75cm^3$

So, the volume of the juice can is $413.75cm^3$

4 0

3 years ago

How to translate the verbal phrase Seven-eighths of r is added to 12 into an algebraic expression

satela [25.4K]

Answer:

'Seven-eighths of $r$ is added to 12' can be represented algebraically as:

$\frac{7}{8}r+12$

Step-by-step explanation:

Given:

Verbal phrase : 'Seven-eighths of $r$ is added to 12'

To write the verbal phrase into an algebraic expression.

Solution:

The verbal phrase 'Seven-eighths' means 7 parts out of 8 and tus can be represented as a fraction = $\frac{7}{8}$

'Seven-eighths of $r$ ' : The phrase represents the fractional part of variable $r$ .

Thus, we have : $\frac{7}{8}\times r=\frac{7}{8}r$

'Seven-eighths of $r$ is added to 12' can be represented algebraically as:

$\frac{7}{8}r+12$

3 0

3 years ago

Which of these careers would not require a university education

finlep [7]

Emergency medical technician is the correct answer I am one and i did not require a university carreer

6 0

4 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

3 years ago

Pls will give brainiest

Ber [7]

Answer:

The answer is D

Step-by-step explanation:

The person who saked this question will find this useless but this is for all the other ppl to come here for the answer

5 0

3 years ago