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salantis [7]
2 years ago
9

Ok last one for today that I cant figure out (6c - 4) - ( c - 3) c = -7 Ty!

Mathematics
1 answer:
horrorfan [7]2 years ago
8 0
9
c
−
4
−
c
2
=
−
7
9
c
-
4
-
c
2
=
-
7
Move
7
7
to the left side of the equation by adding it to both sides.
9
c
−
4
−
c
2
+
7
=
0
9
c
-
4
-
c
2
+
7
=
0

Add
−
4
-
4
and
7
7
.
9
c
−
c
2
+
3
=
0
9
c
-
c
2
+
3
=
0
Factor
−
1
-
1
out of
9
c
−
c
2
+
3
9
c
-
c
2
+
3
.
Tap for more steps...
−
(
c
2
−
9
c
−
3
)
=
0
-
(
c
2
-
9
c
-
3
)
=
0
Multiply each term in
−
(
c
2
−
9
c
−
3
)
=
0
-
(
c
2
-
9
c
-
3
)
=
0
by
−
1
-
1
Tap for more steps...
c
2
−
9
c
−
3
=
0
c
2
-
9
c
-
3
=
0
Use the quadratic formula to find the solutions.
−
b
±
√
b
2
−
4
(
a
c
)
2
a
-
b
±
b
2
-
4
(
a
c
)
2
a
Substitute the values
a
=
1
a
=
1
,
b
=
−
9
b
=
-
9
, and
c
=
−
3
c
=
-
3
into the quadratic formula and solve for
c
c
.
9
±
√
(
−
9
)
2
−
4
⋅
(
1
⋅
−
3
)
2
⋅
1
9
±
(
-
9
)
2
-
4
⋅
(
1
⋅
-
3
)
2
⋅
1
Simplify.
Tap for more steps...
c
=
9
±
√
93
2
c
=
9
±
93
2
The final answer is the combination of both solutions.
c
=
9
+
√
93
2
,
9
−
√
93
2
c
=
9
+
93
2
,
9
-
93
2
The result can be shown in multiple forms.
Exact Form:
c
=
9
+
√
93
2
,
9
−
√
93
2
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Need An Answer ASAP ... THANK YOU !!!
lozanna [386]

Answer:

∠EFG = 48°

Step-by-step explanation:

As FH bisects ∠EFG , ∠EFH = ∠HFG .

We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°

Also, ∠HFG  + ∠EFH = ∠EFG

=> 2(-5x + 89)° = (61 - x)°

=> -10x + 178 = 61 - x

=> 10x - x = 178 - 61

=> 9x = 117

=> x = 117 / 9 = 13

Putting the value of 'x' in ∠EFG gives :-

(61 - x)° = (61 - 13)° = 48°

8 0
3 years ago
4 ft<br> 3 ft!<br> 4 ft<br> 7 ft<br> Area:
Sergio [31]

Answer:336ft

Step-by-step explanation:

multiply

7 0
3 years ago
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I NEED HELP PLEASE IF I GET THIS WRONG ILL FAIL MY EXAM
Finger [1]

3 units
you have to use the distance formula to find the answer. it comes out as u have to square nine and nine squared is 3
7 0
3 years ago
A farmer has a truckload of watermelons to take to market. At the beginning of the trip, the watermelons weigh 1000 kg. 99% of t
Mariulka [41]

Answer:

The weight of watermelon at the end of the trip is <u>500 kg.</u>

Step-by-step explanation:

Given:

The weight of watermelons is 1000kg.

At the beginning of the trip watermelon is 99% of the weight:

99% of 1000kg

\frac{99}{100}\times 1000

=0.99\times 1000

= 990 kg

Now, at the end of the trip it is 98% of weight. So, let x kg of water has been evaporated. So, remaining weight of the watermelon is 1000-x.

If x kg of water is removed, then the amount of water left is 990-x.

As per question, water now weighs 98% of the total weight. So,

98% of (1000-x) = 990-x

\frac{98}{100}\times (1000-x)=990-x

980-0.98x=990-x

-0.98x+x=990-980 (Bringing like terms on one side)

0.02x=10\\x=\frac{10}{0.02}=500\ kg

Therefore, the weight of watermelon at the end of the trip is given as:

Weight = 1000 - x = 1000 - 500 = 500 kg

Therefore, the watermelon weighs 500 kg at the end of trip.

7 0
3 years ago
Read 2 more answers
Please need help on this
SashulF [63]

We can Notice that ∠ABC = ∠ACB

We know that if Two Angles are Equal then Angles Corresponding to those Sides are also Equal.

⇒ AB = AC

⇒ 4x + 4 = 6x - 14

⇒ 6x - 4x = 4 + 14

⇒ 2x = 18

⇒ x = 9

⇒ Length of BC = 2x + 7 = 2(9) + 7 = 18 + 7 = 25 units

4 0
3 years ago
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