Ask question

Ask question

All categories

3 years ago

11

Simpilify : 10a^{3} divided by (15a^{15} + 5a^{5} - 3a^{3})

1 answer:

Ugo [173]3 years ago

5 0

Hopefully it's helpful

You might be interested in

Given these 2 map diagrams which is a function and why?

sergiy2304 [10]

The first one cause no input have more than one output.

4 0

3 years ago

Read 2 more answers

Solve the system y= -x + 7 and y=0.5(x - 3)^2

solniwko [45]

Answer:

(- 1, 8 ) and (5, 2 )

Step-by-step explanation:

Given the 2 equations

y = - x + 7 → (1)

y = 0.5(x - 3)² → (2)

Substitute y = 0.5(x - 3)² into (1)

0.5(x - 3 )² = - x + 7 ← expand and simplify left side

0.5(x² - 6x + 9) = - x + 7 ( multiply both sides by 2 )

x² - 6x + 9 = - 2x + 14 ( subtract - 2x + 14 from both sides )

x² - 4x - 5 = 0 ← in standard form

(x - 5)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 1 = 0 ⇒ x = - 1

Substitute these values into (1) for corresponding values of y

x = 5 : y = - 5 + 7 = 2 ⇒ (5, 2 )

x = - 1 : y = 1 + 7 = 8 ⇒ (- 1, 8 )

8 0

3 years ago

Read 2 more answers

the area bathroom flor measures 2 yards by 3 yards and each custom tilemthat makes up rhe flooring is 1 1/2 square feet how many

NeTakaya

24 tiles
you take 2 yards and 3 yards and multiple them together getting 6 yards, then convert yards to feet resulting in 18 feet, divide that by 1.5 ft and you get 24 tiles.

3 0

3 years ago

Will reward brainleist

Elza [17]

Answer:

$Volume=207.24 mm^{3}$

Step-by-step explanation:

Given:

From the given figure.

Cone height = 7 mm

Cylinder height = 5 mm

Base radius of the cylinder = base radius of the cone = 3 mm

The volume of the given figure is

Volume = volume of cylinder + volume of cone-----------(1)

The volume cylinder is.

$V = \pi r^{2} h$ ----------(2)

Where: r = radius of the cylinder, h = height of the cylinder.

Put the value of height and radius of the cylinder in equation 2.

$V = 3.14\times 3^{2}\times 5$

$V = 3.14\times 9\times 5$

$V = 141.0\ mm^{3}$

The volume of the cylnder is $141.3 mm^{3}$

The volume cone is.

$V = \pi r^{2} \frac{h}{3}$ --------------(3)

Where: r = base radius of the cone, h = height of the cone.

Put the value of height and base radius of the cone in equation 3.

$V = 3.14\times 3^{2}\times \frac{7}{3}$

$V = 3.14\times 9\times \frac{7}{3}$

$V = 3.14\times 3\times 7$

$V = 65.94\ mm^{3}$

The volume of the cone is $65.94 mm^{3}$ .

Put the value of the volume of cone and cylinder in equation 1.

$Volume=141.3+65.94$

$Volume=207.24 mm^{3}$

Therefore, the volume of the given figure is $207.24 mm^{3}$

6 0

3 years ago

Read 2 more answers

Suppose that X ∼ Geom(p) and Y ∼ Geom(r) are independent. Find the probability P (X < Y ).

Murrr4er [49]

$X,Y$ have joint density

$f_{X,Y}(x,y)=f_X(x)f_Y(y)=\begin{cases}pr(1-p)^x(1-r)^y&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

We can find $P(X$ by integrating the joint density over the region in $\Bbb R^2$ where $x$ in the first quadrant, i.e. above the line $y=x$ : $P(X$

using the fact that

$a^n=e^{n\ln a}\implies\displaystyle\int a^n\,\mathrm dn=\frac1{\ln a}e^{n\ln a}+C=\frac1{\ln a}a^n+C$

Then using the same property,

$P(X$

4 0

3 years ago