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lara31 [8.8K]
3 years ago
6

What is 2 3/8 as a percent

Mathematics
1 answer:
Maru [420]3 years ago
6 0
Percent means parts out of 100 so x%=x/100
convert to improper fraction for in x/y form so

2 and 3/8
2=16/8
2 and 3/8=16/8+3/8=19/8
convert bottom number to 100
one way is multiply whole thing by 100/100
19/8 times 100/100=1900/800
divide by 8
237.5/100=237.5%
that is precent
another way is divide completely
19/8=2.375
that is over 1 so convert to over 100 so
2.375/1 times 100/100=237.5/100=237.5%

answe ris 237.5%
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Find the distance between the two points.<br> (-6, – 7), (0,0)
Elden [556K]

Answer:

√85

Step-by-step explanation:

for this, you will probably need to draw a graph. Plot the points, and then you will notice that you can draw a triangle with one side being the x-axis ( go on to (-6,0) then drop down unitll you hit the point (-6;-7)

// use the pythagoream theorem to find the length

the distance of the leg on the x-axis is 6  (calculate 0-(-6))

the distance of the leg that is dropping down is -7 (calculate 0-(-7))

then we have 2 legs and need to find the hypotenuse.

Pythagorean theorem a^2 + b^2 = c^2

substitute :

6^2 + 7^2 = c^2

36+49 = 85

c= √85

8 0
3 years ago
Write the sentence as an equation, 341 is the same as 19 divided by b
Serhud [2]

Answer:

19/b =341

Step-by-step explanation:

Division in algebra is shown in fractions so if you put 19 over b it means 19 divided by b.

8 0
3 years ago
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I need help on this question
polet [3.4K]

certificate of deposit

8 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the verbal descriptions with the co
Daniel [21]

Answer:

Step-by-step explanation:

6 more than a number is 36: x+6=36

36 more than a number is 6: x+36=6

6 times a number is 36: 6x=36

4 0
3 years ago
Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution
Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\

for y=e^{6x}:

y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\

Now we replace in the differential equation  y'' − y' − 30y = 0

for y=e^{-5x}:

25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0

for y=e^{6x}:

36e^{6x}-6e^{6x}-30=0\\36-6+30=0

Now, to know if both function are linearly independent we calculate the Wronskian

W(f,g)=fg'-f'g

W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0

I hope this is useful for you

Best regard

7 0
3 years ago
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