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lilavasa [31]
3 years ago
13

Someone please help, 100 points.

Mathematics
1 answer:
Over [174]3 years ago
5 0
Part 1
Let:
y be the total cost
x be the number of tickets
a be fair admission

Since the fair charges $1.25 per ticket, the equation of the line would look like:

y = 1.25x + a

Since Johnny spent $43.75 and bought 25 tickets, we find a by replacing y with 43.75 and x with 25:

43.75 = 1.25×25 + a

Now solve for a

43.75 = 31.25 + a
43.75 - 31.25 = a
a = 12.50

Going back to the first equation:

y = 1.25x + 12.50


Part 2:
a) Let (9,8) be (x1,y1) and (4,-12) be (x2,y2)
The formula for slope is:
m =  \frac{y2 - y1}{x2 - x1}  \\ m =  \frac{ - 12 - 8}{4 - 9}  \\ m =  \frac{ - 20}{ - 5}  \\ m = 4
b) For the point-slope equation, I'll use (9,8)
Using the formula:
y - y1 = m(x - x1) \\ y - 8 = 4(x - 9)
c) For the slope-intercept form, we solve for y in the point-slope formula:
y - 8 = 4(x - 9) \\ y = 4x - 36 + 8 \\ y = 4x - 28
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3 years ago
5(t - 3) -2t = -30 what is the answer?
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Answer:

t = -5

Step-by-step explanation:

Solve for t:

5 (t - 3) - 2 t = -30

Hint: | Distribute 5 over t - 3.

5 (t - 3) = 5 t - 15:

5 t - 15 - 2 t = -30

Hint: | Group like terms in 5 t - 2 t - 15.

Grouping like terms, 5 t - 2 t - 15 = (5 t - 2 t) - 15:

(5 t - 2 t) - 15 = -30

Hint: | Combine like terms in 5 t - 2 t.

5 t - 2 t = 3 t:

3 t - 15 = -30

Hint: | Isolate terms with t to the left hand side.

Add 15 to both sides:

3 t + (15 - 15) = 15 - 30

Hint: | Look for the difference of two identical terms.

15 - 15 = 0:

3 t = 15 - 30

Hint: | Evaluate 15 - 30.

15 - 30 = -15:

3 t = -15

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 3 t = -15 by 3:

(3 t)/3 = (-15)/3

Hint: | Any nonzero number divided by itself is one.

3/3 = 1:

t = (-15)/3

Hint: | Reduce (-15)/3 to lowest terms. Start by finding the GCD of -15 and 3.

The gcd of -15 and 3 is 3, so (-15)/3 = (3 (-5))/(3×1) = 3/3×-5 = -5:

Answer: t = -5

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If someone can help me with this question please?
Katyanochek1 [597]

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