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Vesnalui [34]
3 years ago
9

Sierra has a total of 61 dimes and quarters in her piggybank. She has 3 more quarters than dimes. The coins have a total value $

10.90. How many dimes and how many quarters does she have? [hint: use the decimal values of the c coins to write an equation.]
Mathematics
1 answer:
cluponka [151]3 years ago
7 0
Since you have two unknowns, you must formulate 2 equations in order to solve the system. Let x be the numbers of dimes and y be the number of quarters. The equations are:

x + y = 61
y = x + 3

Since a dime is 1/10 of a dollar and a quarter is 1/4 of a dollar,
(1/10)x + (1/4)y = 10.90

We made 3 equations. The system is overspecified. Let's just use the first two equations and apply it to the third for verification.

x + (x + 3) = 61
Solving for x,
x = 29
y = 29 + 3 = 32

Verifying,
(1/10)(29) + (1/4)(32) = 10.90

Hence, there are 29 dimes and 32 quarters.
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I hope someone can help me here please don't answer nonsense!​
Wittaler [7]

Answer:

  282°

Step-by-step explanation:

The measure of long arc KLM can be found by first determining the measure of short arc KM. That arc can be found using the inscribed angle theorem.

__

<h3>value of x</h3>

The inscribed angle theorem tells you the measure of arc KM is twice the measure of the inscribed angle KLM that subtends it. This relation can be used to find the value of x, hence the measure of the arc.

  2∠KLM = arc KM

  2(5x -1) = 8x +14

  10x -2 = 8x +14 . . . . . . eliminate parentheses

  2x = 16 . . . . . . . . . . add 2-8x

  x = 8 . . . . . . . . . divide by 2

<h3>measure of arc KM</h3>

The expression for the measure of arc KM can be evaluated.

  arc KM = 8x +14 = 8(8) +14 = 78°

<h3>measure of arc KLM</h3>

The total of arcs of a circle is 360°, so the measure of long arc KLM will bring the total with arc KM to 360°:

  arc KM +arc KLM = 360°

  arc KLM = 360° -arc KM

  arc KLM = 360° -78° = 282°

The measure are long arc KLM is 282°.

7 0
2 years ago
Find all complex solutions of 7x^2-7x+3=0
Sedaia [141]

Answer:

The complex solutions are

x =  (\frac{7-\sqrt{35}  i }{42} , ) x =  \frac{7 + \sqrt{35} i }{42})

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation  7 x² - 7 x +3=0

                     x =  (\frac{-b -\sqrt{b^{2}-4ac } }{2ac} ,  \frac{-b +\sqrt{b^{2}-4ac } }{2ac})

Given standard equation

                         a x² +b x +c =0

 a = 7 , b= -7 and c=3

<u><em>Step(ii):-</em></u>

<u><em></em></u>x =  (\frac{-(-7) -\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)} ,  \frac{-(-7) +\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)})<u><em></em></u>

<u><em></em></u>x =  (\frac{7-\sqrt{(49-84 } }{42} ,  \frac{7 +\sqrt{(49-84 } }{42})<u><em></em></u>

x =  (\frac{7-\sqrt{35i^{2} }  }{42} ,  \frac{7 + \sqrt{35i^{2} }  }{42})

x =  (\frac{7-\sqrt{35}  i }{42} ,  \frac{7 + \sqrt{35} i }{42})

<u><em></em></u>

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Eduardwww [97]

Answer:

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Step-by-step explanation:

y - x = 4

y - (3y) = 4

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y = 2

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Vlada [557]

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Step-by-step explanation: 7x7=49 and 7x5=35

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