Area inside the semi-circle and outside the triangle is (91.125π - 120) in²
Solution:
Base of the triangle = 10 in
Height of the triangle = 24 in
Area of the triangle = 

Area of the triangle = 120 in²
Using Pythagoras theorem,




Taking square root on both sides, we get
Hypotenuse = 23 inch = diameter
Radius = 23 ÷ 2 = 11.5 in
Area of the semi-circle = 

Area of the semi-circle = 91.125π in²
Area of the shaded portion = (91.125π - 120) in²
Area inside the semi-circle and outside the triangle is (91.125π - 120) in².
Answer:
x=9
Step-by-step explanation:
-9x + 1 = -80
-9x = -81 substract 1 from both sides
x= 9 divide both sides by -9
The circumference is 72.22. The formula for circumference is the diameter times pi, which in this case multiplies to about 72.22