A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
Answer:
15.71m
Step-by-step explanation:
circumference of a circle = 2πr
where r = 2.5m
where π = 3.142
we have,
2*3.142*2.5 = 15.71m
therefore the circumference of a circle with a radius 2.5m = 15.71 m
Answer:
y-2x -8
Step-by-step explanation:
your jus gonna right it back because it's parallel which means it's the same thing.
The question says boys/girls = 3/4 so if there are 12 boys in the class you can say:
3/4 = 12/?
and ? is the number of girls which is equal to:
? = 12*3/4 = 9
so if there are 12 boys in the class we will have 9 girls in the class :)))
i hope this is helpful
have a nice day
