There you go!!! Hope I helped :)
Dennis takes care of private swimming pools. He charges $35 to travel to a home and then $40 per hour. The equation t = 35 + 40h
1 answer:
You might be interested in
Answer:
3.67% probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
Find the probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.
This is the pvalue of Z when X = 0.809.
By the Central Limit Theorem
has a pvalue of 0.0367
3.67% probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.
Answer:
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = 3.5
Step-by-step explanation:
Given that:
Consider the following ordered data. 6 9 9 10 11 11 12 13 14
From the above dataset, the highest value = 14 and the lowest value = 6
The median is the middle number = 11
For Q1, i.e the median of the lower half
we have the ordered data = 6, 9, 9, 10
here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.
i.e
median =
median =
median = 9
Q3, i.e median of the upper half
we have the ordered data = 11 12 13 14
The same use case is applicable here.
Median =
Median =
Median = 12.5
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = Q3 - Q1
The interquartile range = 12.5 - 9
The interquartile range = 3.5
Answer:
12.5%
Step-by-step explanation:
First we need to calculate the change in the area of Terry's room this is
108 ft2 - 96 ft2 = 12 ft2
Then we use a direct proportion in order to find the percentage
96 ft2 ----- 100%
12 ft2 ----- p?
Solvin for p we have that
p=12.5