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VashaNatasha [74]
2 years ago
10

Michelle has 3

Mathematics
1 answer:
anyanavicka [17]2 years ago
3 0

Answer: 4/5

Step-by-step explanation:

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Two sailboats are traveling along the same path away from a dock, beginning from different locations at the same time. John’s bo
Sergeu [11.5K]

Answer: C

Step-by-step explanation: It’s C , I had the same question.

3 0
3 years ago
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The longest side in a right triangle is 24 cm, and the second longest side is 20 cm. Find the length of the shortest side
harkovskaia [24]

Answer:

13.3 cm

Step-by-step explanation:

Apply the Pythagorean Theorem:

hyp² = (2nd longest side)² + (shortest side)².  Here the numbers are:

(24 cm)² = (20 cm)² + (shortest side)², or

576 - 400 = 176 = hyp²

Taking the square root of both sides, we get (shortest side) = 13.3 cm

5 0
3 years ago
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A boat rental charges a flat fee of $45 and $4 per hour. Which expression represents the total cost to rent a boat for h hours
vichka [17]

Answer:

45h+ 4

Step-by-step explanation:

you got to divide but the expression is 45h+4

5 0
3 years ago
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
Determine if the conditional and its converse are true. If they are both true, select which biconditional correctly represents t
Ugo [173]
The conditional,  <span>If four points are non-coplanar, then they are non-collinear, </span>is true:

This is, coplanarity is a necessary condition to be collinear.

The converse, <span>If four points are non-collinear, then they are non-coplanar, is false.

A counterexample that disproves this statement is the 4 vertices of a paralelogram, of course they are in a same plane and are not collinear.
</span> 


3 0
3 years ago
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