A karat equals 1/24 part of gold in an alloy [ eg 9 karat gold is 9/24 gold]. How many grams of 9 karat gold must be mixed with
1 answer:
This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
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Like 3 hours I think to make it 410
Answer:
It is A
Step-by-step explanation:
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2 2
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The right answer is 4 hoped i helped
Option B is the correct answer
1KL = 1000L
x KL = 8
Thus, 8/1000
Answer:
<h2>x + 5 < 13</h2>
Step-by-step explanation:
x < 8 <em>add 5 to both sides</em>
x + 5 < 8 + 5
x + 5 < 13