Because the difference between any term and the previous term is a constant, this is an arithmetic sequence because of that constant which is referred to as the common difference, d. Which in this case is -35--38=-32--35=3
Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=initial term, d=common difference, n=term number.
In this case a=-38 and d=3 so
a(n)=-38+3(n-1) which we can simplify to
a(n)=-38+3n-3
a(n)=3n-41, so the 52nd term is:
a(52)=3(52)-41
a(52)=156-41
a(52)=115
Answer:
it is a relationship where the first difference is equal and the second difference is 0
