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2 years ago

What is the value of x in this figure?

Mathematics

1 answer:

dem82 [27]2 years ago

8 0

The lengths of sides of a 30°-60°-90° triangle have the ratio 1 : √3 : 2. Multiplying these values by 5 tells you the sides have the lengths 5 : 5√3 : 10.

The length x of the middle-length side is ...
c. 5√3

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HELP PLEASE ASAP!!!!

vodomira [7]

Answer:

I may be wrong, but I learned that the first slot would be "terms". 4:3 would be an example of a ratio so it couldn't be ratio and a difference is subtracting.

The second slot would not be a geometric sequence because it is not correctly placed on the number line.

Therefore, the answers would be "terms" and "is not"

5 0

3 years ago

Rewrite using positive exponents

Oxana [17]

Answer:

Your selection is appropriate

Step-by-step explanation:

A negative exponent in the numerator is equivalent to a positive exponent in the denominator, and vice versa.

... a⁻² = 1/a²

____

2⁴ multiplies the variable expression no matter which way it is written.

4 0

3 years ago

Which expressions are equal to 105?

Amanda [17]

Answer:

2•2²×100+5.

Step-by-step explanation:

5 0

2 years ago

13. There are 45 employees who each put in 97 hours on a project. What are the total number of hours worked on the project?

Tcecarenko [31]

You would do 45 x 97 which equals 4365

7 0

2 years ago

Use technology or a z-score table to answer the question.

Alik [6]

Answer:

The second choice: Approximately $65.2\%$ of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each $z$ entry has two decimal places.

Let $\mu$ represent the mean of a normal distribution of variable $X$ . Let $\sigma$ be the standard deviation of the distribution. The z-score for the observation $x$ would be:

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question,

$\mu = 240$ .
$\sigma = 9.3$ .

Calculate the z-score for $x_1 = 225$ and $x_2 = 245$ . Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

$\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}$ .

$\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}$ .

The question is asking for the probability $P(225 \le X \le 245)$ (where $X$ is between two values.) In this case, that's the same as $P(-1.61 \le Z \le 0.54)$ .

Keep in mind that the probabilities on many z-table correspond to probability of $P(Z \le z)$ (where $Z$ is no greater than one value.) Therefore, apply the identity $P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1)$ to rewrite $P(-1.61 \le Z \le 0.54)$ as the difference between two probabilities:

$P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61)$ .

Look up the z-table for $P(Z \le 0.54)$ and $P(Z \le -1.61)$ :

$P(Z \le 0.54)\approx 0.70540$ .
$P(Z \le -1.61) \approx 0.05370$ .

$\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}$ .

3 0

3 years ago