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Alisiya [41]
3 years ago
10

What is the missing reason in the proof? HELP!! ASAP

Mathematics
1 answer:
motikmotik3 years ago
5 0

Answer:

c mark me as brainliest

Step-by-step explanation:

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The fare for a taxi cab is $2.50 per passenger and $0.75 for each mile. A group of friends has $22.00
xeze [42]

For this case we have to:

x: Let the variable representing the number of people to travel in the group

y: Let the variable representing the number of miles traveled.

If friends only have $22 then we have the following inequality:

2.50x + 0.75y \leq22

Now, if there are three people in the group we have that x = 3.

2.50 (3) + 0.75y \leq22\\7.5 + 0.75y \leq22\\0.75y \leq22-7.5\\0.75y \leq14.5\\y\leq \frac {14.5} {0.75}\\y\leq19.33

The taxi can travel a maximum of 19.33 miles.

On the other hand, if the group wants to travel 10 miles then we have to y = 10.

2.50x + 0.75 (10) \leq22\\2.50x + 7.5 \leq22\\2.50x \leq22-7.5\\2.50x \leq14.5\\x\leq \frac {14.5} {2.50}\\x \leq5.8

Thus, they could travel a maximum of 5 people.

ANswer:

2.50x + 0.75y \leq22

Traveling 3 people, the taxi can travel a maximum of 19.33 miles

Traveling 10 miles, a maximum of 5 people can travel

7 0
3 years ago
Seth can build a doghouse in 6 hours. Violet can build a doghouse in 5 hours. How long will it take to build the dog house if th
Sliva [168]

Answer:

It will take a total of 2.73 hours if they worked together

Step-by-step explanation:

Here, we are seeking to calculate the joint rate.

Let the amount of work to be done is say x

Seth’s rate will be x/6 , while violet’s rate will be x/5

Their joint rate will be ;

x/6 + x/5 = 11x/30

The time it will take them to build the house together will be equal to the amount of work divided by the joint rate.

That will be x divided by 11x/30

= x * 30/11x

= 30/11 hours which is Approximately 2.73 hours

4 0
4 years ago
Can someone please help me answer this one question plzzzzz
likoan [24]

Answer:

1. B

2. A

3. C

7 0
3 years ago
Read 2 more answers
I WILL MARK THE BRAINLIEST!!! One math question. please explain as well
8090 [49]
Surface area of a sphere=4pi(r^2)
Volume of a sphere=(4/3)pi(r^3)
You need to find the r value to calculate surface area, so I'll solve for that first.
(4/3)pi(r^3)=2254pi
(4/3)(r^3)=2254
r^3=1690.5
r=(1690.5)^(1/3), around 11.9126m
Substitute this in to find surface area
A=4pi(r^2)=4pi(11.9126)^2
=1783.2818 m^2
5 0
4 years ago
You run at a rate of 4 mph and your friend runs at a rate of 3.5 mph Your friend starts running 10 minutes before you, and you b
irga5000 [103]

Answer:

A)

<u>i) Your speed: 0.067 miles per minute</u>

<u>ii) Your friend's speed: 0.058 miles per minute</u>

<u>B) You will not catch up with your friend by the time your friend stops running.</u>

Explanation:

<u>A. Find your speed and your friend's speed in miles per minute</u>

<u>i) Your speed:</u>

You know your speed is 4 mph, which is 4 miles per hour. To find you spedd in miles per minute you must multiply by the factor that relates hours and minutes:

  • 1 hour = 60 min

  • 1 = 1 hour / 60 min

  • 4 miles / hour × 1 hour / 60 min = 4 miles / 60 min ≈ 0.0667 miles/min

         (note that the unit hour is in the denominator of the first fraction and in the numerator of the second fraction, so they cancel each other, and the final units are miles / min).

<u>ii) Your friend's speed</u>

  • 3.5 miles / hour × 1 hour / 60 min = 3.5 miles / 60 min ≈ 0.0583 miles / min.

(again, the unit hour is in the denominator of the first fraction and in the numerator of the second fraction, so they cancel each other, and the final units are miles / min).

<u>B. Will you catch up with your friend by the time your friend stops running?</u>

To find whether you catch up your friend you can use a system of equation that relates the times and the distances run by each one.

i) The distance run by you is equal to your time times your speed:

  • d₁ = 0.0667 miles / min × t₁

ii) The distance run by your friend is equal to his time times his speed.

  • d₂ = 0.0583 miles / min × t₂

Since you friend started running 10 minutes before you, his time is 10 minutes more than yours, i.e. t₂ = 10 min + t₁.

Now you can write the second equation as:

  • d₂ = 0.0583 miles / min × (10 min + t₁).

And since you want to determine whether you catch up him/her by the time he/she stops running, you can determine the time when both distances would be equal:

  • d₁ = d₂

  • 0.0667 miles / min × t₁ = 0.0583 miles / min × (10 min + t₁)

To solve the equation I will ignore the units (normal procedure to solve equations):

  • 0.0667 t₁ = 0.0583 (10 + t₁)

  • 0.0667 t₁ = 0.583 + 0.0583t₁

  • 0.0667 t₁ - 0.0583 t₁ = 0.583

  • 0.0084 t₁ = 0.583

  • t₁ = 0.583 / 0.0084 ≈ 69 min

That is the time you need to catch up your friend, 69 min. Since your friend started 10 min before you and will stop after half an hour (30 min), you will not catch up with your friend before the time your friend stops running.

5 0
4 years ago
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