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Alisiya [41]
3 years ago
10

What is the missing reason in the proof? HELP!! ASAP

Mathematics
1 answer:
motikmotik3 years ago
5 0

Answer:

c mark me as brainliest

Step-by-step explanation:

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Look at the following 1040EZ calculate the adjusted gross income you should enter on the line 4
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The answer is $1,697.

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Solve the following dividend problem.
brilliants [131]

A.

To get dividend per share, we need to divide total dividend by total numbers of shares outstanding.

Dividend per share = \frac{40,000}{50,000}=0.8 dollars.


B.

Since per share you get $0.8, for 100 shares you will get 0.8*100=80 dollars.

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ANSWER:

A. $0.8 per share

B. $80 (and that is 0.2% of total dividend)

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Given the function f(x) = 6x^2 −13, what is f(-3)?
Naya [18.7K]
<h3>Answer: 41</h3>

Work Shown:

f(x) = 6x^2 - 13

f(x) = 6(x)^2 - 13

f(-3) = 6(-3)^2 - 13 ... replace every x with -3; use PEMDAS to simplify

f(-3) = 6(9) - 13

f(-3) = 54 - 13

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7 0
3 years ago
If f(x)=1/x and g(x)=x^2-4x. What two numbers are not in the domain of f o g?
statuscvo [17]

The composed fraction f \circ g means that the input of f(x) is the ouput of g(x).

So, the chain is

x \mapsto g(x) \mapsto f(g(x)) = f\circ g = \dfrac{1}{g(x)} = \dfrac{1}{x^2-4x}

The domain of f(x) is composed by all inputs which are not zero, otherwise we would have a zero denominator.

So, since f(x) doesn't accept 0 as an input, and we want to feed it with g(x), we conclude that g(x) can't be zero.

So, we have

f \circ g = f(g(x)) = f(x^2-4x) = \dfrac{1}{x^2-4x} \implies x^2-4x \neq 0

Since

x^2-4x = x(x-4)

we have

x^2-4x = 0 \iff x(x-4) = 0 \iff x=0 \lor x=4

Since these two points cases g(x) to vanish, they can't be accepted as inputs by f(x).

5 0
3 years ago
Percent of change $75 to $25
Vesnalui [34]
66.67%. hope i helped man
7 0
3 years ago
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