Answer:
Im going with b because i cant see the picture
Explanation:
Answer:
$1,101.32
Explanation:
Simple interest accounts balances are calculated using the following formula
A = P ( 1 + rt)
where:
A = final account balance
P = starting balance
r = interest rate (annually) percentage divided by 100
t = years
Therefore, we can plug in the values provided in this formula and solve for P which would be the amount that Kremena needs to deposit.
1,250 = P ( 1 + (0.045 * 3))
1,250 = P * 1.135 ... divide both sides by 1.135
1,101.32 = P
Finally, we can see that Kremena would need to deposit a total of $1,101.32 to have the amount that she wants after 3 years.
Answer:
Dear Professor, I just wanted to let you known I failed my homework because, after I moved I have no access to the internet. I am very sorry.
Answer and Explanation:
The computation of the service level and the corresponding optimal stocking level is shown below:
Given that
Selling price = SP = $4.50
Cost price = CP = $3.00
So,
Salvage value = V = $1.50
Average daily demand (d) = 35 quarts
The standard deviation of daily demand = 4 quarts
based on the above information
Overage cost = (Co) is
= CP - V
= $3.00 - $1.50
= $1.50
Now
Underage cost= (Cu)
= SP - CP
= $4.50 - $3.00
= $1.50
So,
Service level is
= Cu ÷ (Co + Cu)
= 1.50 ÷ (1.50 + 1.50)
= 1.50 ÷ 3.00
= 0.50
= 50%
Now
At 50 % service level, the value of Z is 0
So,
Optimal stocking level is
= d + Z × standard deviation
= 35 + (0 × 4)
= 35 + 0
= 35 quarts
