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3 years ago

What is 6 times -64 times 3

Mathematics

2 answers:

horsena [70]3 years ago

7 0

The answer is -1152
Hope it helps!!

Alexxx [7]3 years ago

6 0

6(-64)(3) = -1152 The answer is -1152 because 6 × (-64) = -384 and -384 × 3 = -1152.

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Which of the following expressions represents "no more than 5”?

zepelin [54]

Answer:

"no more than 5"

"less than or equal to 5"

$x \le 5$ .

I can't see your inequalities or the thing your question called expressions.

Step-by-step explanation:

If is no more than it is less than or equal to.

So no more than 5 means less than or equal to 5.

$x \le 5$ .

8 0

3 years ago

The formula for interest is I=Prt. Describe what these letters stand for. Is the formula the same if you are charged interest on

prisoha [69]

Answer:

I stand for interest

P stand for principle

R stand for rate

T stand for time

There are the same.

7 0

3 years ago

Whats the difference between coplanar and collinear

Sergio [31]

In terms of points, a point that is coplanar is one that lies anywhere on the given plane while a point that is collinear is a point that lies anywhere on the given line.

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3 years ago

Read 2 more answers

The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours. Find

dezoksy [38]

Answer: C.-1.5

Step-by-step explanation:

Given: The burning time of a very large candle is normally distributed with mean $(\mu)$ of 2500 hours and standard deviation $(\sigma)$ of 20 hours.

Let X be a random variable that represent the burning time of a very large candle.

Formula: $Z=\dfrac{X-\mu}{\sigma}$

For X = 2470

$Z=\dfrac{2470-2500}{20}\\\\\Rightarrow\ Z=\dfrac{-30}{20}\\\\\Rightarrow\ Z=\dfrac{-3}{2}\\\\\Rightarrow\ Z=-1.5$

So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5

Hence, the correct option is C.-1.5.

7 0

2 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

<u>Step-by-step explanation:</u>

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

3 years ago