STEP 1- since 6 doesn't contain the variable to solve for move it to the right side of the equation by subtracting 6 from both sides
X^2-8X=-6
STEP 2- create a trinomial square on the left side of the equation find the value that is equal to the square of half of b the coefficient of x
(b/2)^2 =(-4)^2
STEP 3- add the term to each side of the equation
x^2-8x+(-4)^2=-6=(-4)
STEP 4- simplify the equation
x^2-8x+16=10
STEP 5- factor the perfect trinomial square into (x-4)^2
(x-4)^2=10
STEP 6-solve the equation for x
x=4= square root of 10
Answer:
there are 6 dogs
Step-by-step explanation:
x = dogs
x= 2 + 4
x = 6
The expressions that are equivalent when m = 1 and m = 4 is;
Option B: 3m + 4 and m + 4 + 2m
We are given m = 1 and m =4;
A) 5m - 3 and 2m + 5 + m
B) 3m + 4 and m + 4 + 2m
C) 2m + 7 and 3m - 3 + m
D) 5m + 3 and 4m + 2 + 2m
For option B; 3m + 4 and m + 4 + 2m
Let's put m = 1
3(1) + 4 = 7
Also, 1 + 4 + 2(1) = 7
Similarly, let us put 4 for m to get;
3(4) + 4 = 16
Also, 4 + 4 + 2(4) = 16
In both cases, the expressions are equivalent and as such option B is the right one.
Read more about algebra simplifications at; brainly.com/question/4344214
99.99 x (7%/100)= 6.9993
99.99+6.9993= 106.9893 (round up)
ANWSER- $106.99
Hope this helped.
Answer:
(a) 
The expected number in the sample that treats hazardous waste on-site is 0.383.
(b) 
There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Step-by-step explanation:
Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.
N = 209
Only eight of these facilities treated hazardous waste on-site.
r = 8
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?
n = 10
The expected number in the sample that treats hazardous waste on-site is given by




Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site
The probability is given by
For the given case, we have
N = 209
n = 10
r = 8
x = 4




Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.