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oee [108]
3 years ago
15

25 POINTS!!!! PLEASE EXPLAIN TO ME STEP BY STEP!

Mathematics
2 answers:
Harman [31]3 years ago
8 0
-x-y-z=-8
-x-y-z=-8

Let's solve for x.<span><span><span><span>−x</span>−y</span>−z</span>=<span>−8
</span></span>Step 1: Add y to both sides.<span><span><span><span><span>−x</span>−y</span>−z</span>+y</span>=<span><span>−8</span>+y</span></span><span><span><span>−x</span>−z</span>=<span>y−8
</span></span>Step 2: Add z to both sides.<span><span><span><span>−x</span>−z</span>+z</span>=<span><span>y−8</span>+z</span></span><span><span>−x</span>=<span><span>y+z</span>−8
</span></span>Step 3: Divide both sides by -1.<span><span><span>−x</span><span>−1</span></span>=<span><span><span>y+z</span>−8</span><span>−1</span></span></span><span>x=<span><span><span>−y</span>−z</span>+8
</span></span>Answer: <span>x=<span><span><span>−y</span>−z</span>+<span>8</span></span></span>
Feliz [49]3 years ago
3 0
Easy peassy
so basically what you would try to do is eliminate one type of variable from 2 different equations
look, we have
2x+2z=4
that already has y eliminated
so we just need to eliminate y from another equation

so

we can eliminate the y from the 2nd equation
multiply the first equation by 4 and add to 2nd equation

-4x-4y-4z=-32
<u>-4x+4y+5z=7 +</u>
-8x-0y+1z=-25

-8x+z=-25


we have
-8x+z=-25 and
2x+2z=4

we can elminate the z's
multiply first (top) equation by -2 and add to bottom equaton
16x-2z=50
<u>2x+2z=4 +</u>
18x=54

18x=54
divide both sides by 18
x=3

sub back
2x+2z=4
2(3)+2z=4
6+2z=4
minus 6 both sides
2z=-2
divide 2
z=-1

sub back

-x-y-z=-8
-3-y-(-1)=-8
-3-y+1=-8
-2-y=-8
add 2 to both sides
-y=-6
times -1
y=6


x=3
y=6
z=-1
(x,y,z)
(3,6,-1)
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Irina18 [472]

Answer:

\bf C)\: -\cfrac{1}{32}

Step-by-step explanation:

\tt \cfrac{1}{2^{-2}x^{-3}y^5}

\tt x=2\\y=-4

~

Substitute ''x'' with '2' & 'y' with "-4":-

\tt \cfrac{1}{2^{-2}\times \:2^{-3}\left(-4\right)^5}

First let's solve \tt 2^{-2}\times \:\:2^{-3}\left(-4\right)^5

\tt 2^{-2}\times \:2^{-3}=\boxed{\cfrac{1}{32} }

\tt \cfrac{1}{32}\left(-4\right)^5

Calculate exponents:- -4^5= -1024

\tt \cfrac{1}{32}\left(-1024\right)

Remove parentheses, apply rule:- \tt a\left(-b\right)=-ab

\tt-\frac{1}{32}\times \:1024

\tt \cfrac{1}{32}\times \cfrac{1024}{1}

Apply fraction rule:-

\tt -\cfrac{1\times \:1024}{32\times \:1}

\tt \cfrac{1024}{32}

Divide numbers:-

\tt -32

Now that we're done factoring the denominator let's bring down the numerator which is ' 1 ':-

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PLEASE HELP!!!!!!
galina1969 [7]

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A = π r^2
A = 9^2 <span>π
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if using </span>π = 3.14 then

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