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Svetach [21]
3 years ago
13

The scale of the map is missing.The actual distance from liberty to west quall is 72 miles, and it is 6 inches on the map

Mathematics
2 answers:
Elenna [48]3 years ago
5 0

Answer:

a.)1 inches =72/7 miles

b.) 30.86

Step-by-step explanation:

Given: Distance from liberty to west quall is 72 miles and it is 7 inches on the map.

To find : The scale on the map.

So, In 7 inches distance covered = 72 miles

In 1 inches distance covered=

Therefore, The scale on the map is

1 inches=   miles.

b) Given: Foston is between liberty and west quall and is 4 inches from liberty on the map.

To find : Distance between foston to west quall (F to W)        

We know the scale of map i.e.  1 inches=   miles.

Firstly, we find the distance covered from liberty to foston i.e. 4 inches on the map

4 inches =   miles

4 inches = 41.14 miles

Now the distance between liberty to west quall (L to W)= 72 miles

and the distance between liberty to foston (L to F)= 41.14 miles

Therefore, the distance between foston to west quall(F to W)=distance(L to W)- distance(L to F) (Refer the attached graph)

Distance(F to W)= distance(L to W)- distance(L to F)

Distance(F to W)=72-41.14 miles = 30.86 miles  

krek1111 [17]3 years ago
4 0
72 miles ... 6 inches
x miles = ? ... 1 inch

If you would like to know the scale of the map, you can calculate this using the following steps:

72 * 1 = 6 * x
72 = 6 * x     /6
x = 72 / 6
x = 12 miles

Result: 12 miles represent 1 inch on the map.
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The scale drawing of a concrete pad has a length of 9.1 cm, a depth of 2.2 cm and a width of 3.8 cm.
pogonyaev

Answer:

242 cm  

Step-by-step explanation:

1. Find the scale factor

A scale factor (SF) is the ratio of two corresponding lengths in similar figures.

SF = actual distance/scale distance

If the scale width is 3.8 cm,

SF = 418 cm/3.8 cm = 110

2. Calculate the actual depth

110 = actual depth/2.2 cm

Actual depth = 110 × 2.2 cm = 242 cm

8 0
3 years ago
Read 2 more answers
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

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5 0
2 years ago
6. The perimeter of a parallelogram is 100 meters. The width of the parallelogram is 4 meters less than its length. Find the len
Ierofanga [76]

Answer:

x = 23, and y = 27.

Step-by-step explanation:

Lets say,

x = width

y = length

this means,

x(2) + y(2) = 100

It also says that the width is 4 meters less than the length.

if we put that into equation form it would look like this,

y - 4 = x

using these 2 equations, we can use the subustusion method to find the x.

x(2) + y(2) = 100

turns in to this :

step 1.     (y - 4) (2) + y(2) = 100 - given

step 2.      2y -8 + 2y = 100 -  distribute

step 3.      4y -8 = 100 - Combine like terms

step 4.       4y  = 108 - Get rid of the 8

step 5        4y/4  = 108 /4 - divide

step 6 .          y = 27

So if y is 27, then

x(2)  +  27(2) = 100

x(2) + 54 = 100

100 - 54 = 46, so x(2) is 46, but to get x, we need to divide 46 by 2, since x multiplied by 2 equals 46.

46  / 2 = 23 = x

so x = 23, and y = 27.

and the rule that y - 4 = x still applies, since 27 - 4 = 23.

I hope this wasn't confusing! It did take a long time tho.

5 0
3 years ago
A pink paint mixture uses 4 cups of white paint for every 3 cups of red paint.
Flura [38]

Answer:

cant see the table

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
3y2 + 2xy + 1 + 3x + y + 2x2​
meriva

Answer:

Simplified, it would be 2x^2+2xy+3y^2+3x+y+1 so that's your answer.

8 0
3 years ago
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