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BartSMP [9]
4 years ago
13

A light flashes every 1 minute 15 seconds. another flashes every 1 minute 40 seconds. suppose they flash together at certain tim

e. what is the shortest amount of time that will elapse before both lights will again flash together?
Mathematics
2 answers:
ASHA 777 [7]4 years ago
6 0

Answer:

5 minutes

Step-by-step explanation:

To get the response to this question, it would be required to convert both times to seconds alone.

For the first, the time It takes to flash is 1 minute 15 seconds which is same as 75 seconds

For the second, it takes 1 minute 40 seconds which is same as 100 seconds.

Now to get the time they would flash together, we need to know their lowest common multiples. The values involved are 75 and 100. Thus, the lowest common multiple of both is 300.

This is equivalent to 300 seconds which is 5 minutes time

vlabodo [156]4 years ago
5 0

Answer:

Answer:

5 minutes

Step-by-step explanation:

To get the response to this question, it would be required to convert both times to seconds alone.

For the first, the time It takes to flash is 1 minute 15 seconds which is same as 75 seconds

For the second, it takes 1 minute 40 seconds which is same as 100 seconds.

Now to get the time they would flash together, we need to know their lowest common multiples. The values involved are 75 and 100. Thus, the lowest common multiple of both is 300.

This is equivalent to 300 seconds which is 5 minutes time

Step-by-step explanation:

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which equation represents an exponential function that passes through the point (2, 80)? f(x) = 4(x)5 f(x) = 5(x)4 f(x) = 4(5)x
pav-90 [236]

we know that

if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function

we proceed to verify each case  if the point (2,80) satisfied the exponential function

<u>case A</u>  f(x)=4(x^{5})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=4(2^{5})=128

128\neq 80

therefore

the exponential function  f(x)=4(x^{5}) not passes through the point (2,80)

<u>case B</u>  f(x)=5(x^{4})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=5(2^{4})=80

80=80

therefore

the exponential function f(x)=5(x^{4}) passes through the point (2,80)

<u>case C</u>  f(x)=4(5^{x})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=4(5^{2})=100

100\neq 80

therefore

the exponential function f(x)=4(5^{x}) not passes through the point (2,80)

<u>case D</u>  f(x)=5(4^{x})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=5(4^{2})=80

80=80

therefore

the exponential function f(x)=5(4^{x}) passes through the point (2,80)

therefore

<u>the answer is</u>

f(x)=5(x^{4})

f(x)=5(4^{x})

7 0
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For every 1girl there are 2boys

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(I got all of this from google so i hope it’s right!)
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Answer:

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Step-by-step explanation:

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then divide by .25 on both sides

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